George's page contains twice as many typed words as Bill's page and Bill's page contains 50 fewer words than Charlie's page. If
each person can type 70 words per minute, after one minute, the difference between twice the number of words on Bill's page and the number of words on Charlie's page is 220. How many words did Bill's page contain initially?
Given: George<span>'s page contains twice as many typed words as Bill's page </span><span>Bill's page contains 50 fewer words than Charlie's page </span><span>each person can type 70 words per minute, after one minute, the difference between twice the number of words on Bill's page and the number of words on Charlie's page is 220
Let Charlie's page be x. Let Bill's page be x - 50 Let George's page be 2(x-50)
After 1 minute: Charlie's page: x + 70 Bill's page: x - 50 + 70 George's page: 2(x-50) + 70
Difference between George's page and Charlie's page is 220.
[2(x-50) + 70] - (x + 70) = 220 2x - 100 + 70 - x - 70 = 220 2x - x - 100 + 70 - 70 = 220 x - 100 = 220 x = 220 + 100 x = 320
</span>Let Charlie's page be x. → x = 320 Let Bill's page be x - 50 → x - 50 = 320 - 50 = 270 Let George's page be 2(x-50) → 2(x-50) = 2(320-50) = 2(270) = 540
The answer is 12 I believe. This is because we know one of the lengths which is 2. And then we can use the second rectangle to figure out the second side length.
Please forgive me if I am wrong. Thank you and have a nice day!
