Answer:
9 and 10
Step-by-step explanation:
Answer:
The distance between the two airplanes (to the nearest mile) is 1058 miles.
Step-by-step explanation:
An airplane A is at a location 800 miles due west of city X. So AX = 800 miles.
Another airplane is at a distance of 1,200 miles southwest of city X. So BX = 1200 miles.
The angle at city X created by the paths of the two planes moving away from city X measures 60°. So angle ∠AXB = 60°.
In triangle ΔAXB, AX = 800 miles, BX = 1200 miles, ∠AXB = 60°.
Using law of cosines:-
AB² = AX² + BX² - 2 * AX * BX * cos(∠AXB).
AB² = 800² + 1200² - 2 * 800 * 1200 * cos(60°).
AB² = 640000 + 1440000 - 2 * 960000 * 1/2
AB² = 2080000 - 960000
AB² = 1120000
AB = √(1120000) = 1058.300524
Hence, the distance between the two airplanes (to the nearest mile) is 1058 miles.
Answer:
..................................
Answer:
(B) Subtract 3x from both sides of the equation, and then divide both sides by 2.
Can't read the second question fully.
(A) 0.53
Step-by-step explanation:
Number 1:
If we have the equation 
, our first goal is to get rid of the x term on one side.
To do this we can subtract 3x from both sides. This leaves our equation to 
. To find x, we want to divide both sides by 2 since 2x divided by 2 is just x. Our goal is to isolate x. This leaves 
.
<em>I couldn't read Number 2 fully - I'm sorry :c</em>
<em></em>
Number 3:
Given the equation 
, we want to isolate x on one side.
To do this, we first apply the distributive property to the left side.
Now subtract 0.6 from both sides:
And divide both sides by 3.
This rounds to 0.53.
Hope this helped!
