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JulijaS [17]
2 years ago
14

Use the net below to determine the surface area of the cylinder. (Use 3.14 for π.) 640.56 cm^2 339.12 cm^2 753.6 cm^2 512.56 cm^

2

Mathematics
1 answer:
Elena L [17]2 years ago
8 0

Answer:

<u>The correct answer is C.  753.60 cm²</u>

Step-by-step explanation:

Let's recall that the formula for the surface area of a cylinder is:

S = 2πrh + 2πr²

r = 6

h = 14

Replacing with the values we know:

S = 2 * 3.14 * 6 * 14 + 2 * 3.14 * 6²

S = 527.52 + 226.08

<u>S = 753.60 cm²</u>

<u>The correct answer is C.  753.60 cm²</u>

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kotegsom [21]

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P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}

Step-by-step explanation:

The logistic equation is the following one:

P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}

In which P(t) is the size of the population after t years, K is the carrying capacity of the population, r is the decimal growth rate of the population and P(0) is the initial population of the lake.

In this problem, we have that:

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species in that lake) to be 2,000. This means that P(0) = 80, K = 2000.

The number of fish tripled in the first year. This means that P(1) = 3P(0) = 3(80) = 240.

Using the equation for P(1), that is, P(t) when t = 1, we find the value of r.

P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}

240 = \frac{2000*80e^{r}}{2000 + 80(e^{r} - 1)}

280*(2000 + 80(e^{r} - 1)) = 160000e^{r}

280*(2000 + 80e^{r} - 80) = 160000e^{r}

280*(1920 + 80e^{r}) = 160000e^{r}

537600 + 22400e^{r} = 160000e^{r}

137600e^{r} = 537600

e^{r} = \frac{537600}{137600}

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\ln{e^{r}} = \ln{3.91}

r = 1.36

This means that the expression for the size of the population after t years is:

P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}

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