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iren [92.7K]
3 years ago
8

6th grade math I mark as brainliest

Mathematics
2 answers:
LUCKY_DIMON [66]3 years ago
6 0

Answer:

D: A rhombus is always a parallelogram

Step-by-step explanation:

A rhombus is a quadrilateral, and it is also a parallelogram. However, a parallelogram is not always a rhombus.

skad [1K]3 years ago
3 0

Answer:

A rhombus is always a parallelogram

Step-by-step explanation:

it's lines parallel to the other side

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Five bikers join a race. In how many possible ways can they be arranged as
PolarNik [594]

Answer:

60 different possibilities

Step-by-step explanation:

Number of bikers = 5

Positions = first, second and third

First positions = all 5 riders can take the first spot = 5 possibilities

Second spot = position 1 has been filled hence number of possibilities = ( 5 - 1) = 4

Third spot = position 1 and 2 has been filled ; number of possibilities =. (5 - 2). = 3

Number of possible arrangements :

5 * 4 * 3 = 60 different possibilities

6 0
2 years ago
(cos6x+6cos4x+15cos2x+10)/(cos5x+5cos3x+10cosx)=?
Tasya [4]
Do you mean <span><span><span><span>cos6</span>x+6<span>cos4</span>x+15<span>cos2</span>x+10</span><span><span>cos5</span>x+5<span>cos3</span>x+10cosx</span></span>  ?</span> or <span><span><span>cos6x+6cos4x+15cos2x+10</span><span>cos5x+5cos3x+10cosx</span></span>  ?</span> or <span><span><span><span>cos6</span>x+6<span>cos4</span>x+15<span>cos2</span>x+10</span><span><span>cos5</span>x</span></span>+5<span>cos3</span>x+10cosx  ?</span> or <span><span><span>cos6x+6cos4x+15cos2x+10</span><span>cos5x</span></span>+5cos3x+10cosx  <span>?</span></span>
7 0
3 years ago
360 is divisible by which of the following numbers 2,3,4,5,6,9, or 10
alukav5142 [94]

Answer:

360 is divisible by all numbers 2,3,4,5,6,9 or 10 .

Step-by-step explanation:

Given : 360

To find : 360 is divisible by which of the following numbers 2,3,4,5,6,9, or 10

Solution : We have given

Numbers 2,3,4,5,6,9, or 10.

For number = 2

\frac{360}{2} = 180.

For number = 3

\frac{360}{3} = 120.

For number = 4

\frac{360}{4 } = 90.

For number = 5

\frac{360}{5 } = 72.

For number = 6

\frac{360}{6 } = 60.

For number = 9

\frac{360}{9 } = 40.

For number = 10

\frac{360}{10 } = 36

Therefore, 360 is divisible by all numbers 2,3,4,5,6,9 or 10 .

8 0
3 years ago
Read 2 more answers
Find the two intersection points
bogdanovich [222]

Answer:

Our two intersection points are:

\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)

Step-by-step explanation:

We want to find where the two graphs given by the equations:

\displaystyle (x+1)^2+(y+2)^2 = 16\text{ and } 3x+4y=1

Intersect.

When they intersect, their <em>x-</em> and <em>y-</em>values are equivalent. So, we can solve one equation for <em>y</em> and substitute it into the other and solve for <em>x</em>.

Since the linear equation is easier to solve, solve it for <em>y: </em>

<em />\displaystyle y = -\frac{3}{4} x + \frac{1}{4}<em />

<em />

Substitute this into the first equation:

\displaystyle (x+1)^2 + \left(\left(-\frac{3}{4}x + \frac{1}{4}\right) +2\right)^2 = 16

Simplify:

\displaystyle (x+1)^2 + \left(-\frac{3}{4} x  + \frac{9}{4}\right)^2 = 16

Square. We can use the perfect square trinomial pattern:

\displaystyle \underbrace{(x^2 + 2x+1)}_{(a+b)^2=a^2+2ab+b^2} + \underbrace{\left(\frac{9}{16}x^2-\frac{27}{8}x+\frac{81}{16}\right)}_{(a+b)^2=a^2+2ab+b^2} = 16

Multiply both sides by 16:

(16x^2+32x+16)+(9x^2-54x+81) = 256

Combine like terms:

25x^2+-22x+97=256

Isolate the equation:

\displaystyle 25x^2 - 22x -159=0

We can use the quadratic formula:

\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, <em>a</em> = 25, <em>b</em> = -22, and <em>c</em> = -159. Substitute:

\displaystyle x = \frac{-(-22)\pm\sqrt{(-22)^2-4(25)(-159)}}{2(25)}

Evaluate:

\displaystyle \begin{aligned} x &= \frac{22\pm\sqrt{16384}}{50} \\ \\ &= \frac{22\pm 128}{50}\\ \\ &=\frac{11\pm 64}{25}\end{aligned}

Hence, our two solutions are:

\displaystyle x_1 = \frac{11+64}{25} = 3\text{ and } x_2 = \frac{11-64}{25} =-\frac{53}{25}

We have our two <em>x-</em>coordinates.

To find the <em>y-</em>coordinates, we can simply substitute it into the linear equation and evaluate. Thus:

\displaystyle y_1 = -\frac{3}{4}(3)+\frac{1}{4} = -2

And:

\displaystyle y _2 = -\frac{3}{4}\left(-\frac{53}{25}\right) +\frac{1}{4} = \frac{46}{25}

Thus, our two intersection points are:

\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)

6 0
2 years ago
Help me with this please! :)
Ivenika [448]

Answer:

28

36

40

44

just do the number +1 and ×4

4 0
2 years ago
Read 2 more answers
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