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Triss [41]
4 years ago
13

Are the actions legal or illegal?

Computers and Technology
1 answer:
garik1379 [7]4 years ago
3 0

Answer:

No, Company will not pay

Explanation:

At the last point of the final deal, any significant sum of money does not fall into the frame.

It was important to address the exact amount needed to update the research on agriculture. They might be asking for inflated amounts.

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Which open-sourced packet capture tool uses linux and mac os x operating systems?
Leto [7]

Tcpdump is an open-sourced packet capture tool which uses Linux and Mac OS X operating systems.

<h3>What is tcpdump?</h3>

Tcpdump can be defined as an open-sourced packet capture tool that is typically used to monitor and record TCP/IP traffic that are passing through a network and most Unix-like operating systems such as Linux.

This ultimately implies that, tcpdump is an open-sourced packet capture tool which makes use of Linux and Mac OS X operating systems.

Read more on tcpdump here: brainly.com/question/14485515

#SPJ12

5 0
3 years ago
find_cow(name, cows) Given a name and a Python list of Cow objects, return the Cow object with the specified name. If no such Co
nadya68 [22]

Using the computational knowledge in python it is possible to write a code that Given a name and a Python list of Cow objects

<h3>Writting the code in python:</h3>

<em>def load_cows(filename):</em>

<em>      cow_dict = dict()</em>

<em>    f = open(filename, 'r')</em>

<em> </em>

<em>    for line in f:</em>

<em>        line_data = line.split(',')</em>

<em>        cow_dict[line_data[0]] = int(line_data[1])</em>

<em>    return cow_dict</em>

<em>def greedy_cow_transport(cows, limit=10):</em>

<em>       trips = []</em>

<em>    cowsCopy = cows.copy()</em>

<em>    sortedCows = sorted(cowsCopy.items(), key=lambda x: x[1], reverse = True)</em>

<em>    while sum(cowsCopy.values()) > 0:</em>

<em>        ship = []</em>

<em>        total = 0</em>

<em>        for cow, value in sortedCows:</em>

<em>            if cowsCopy[cow] != 0 and value + total <= limit:</em>

<em>                ship.append(cow)</em>

<em>                total += value</em>

<em>                cowsCopy[cow] = 0</em>

<em>        trips.append(ship)</em>

<em>    return trips</em>

<em>def brute_force_cow_transport(cows,limit=10):</em>

<em>     trips = []</em>

<em>     possibilities = []</em>

<em>    for i in power_list:</em>

<em>        ship = []</em>

<em>        for j in i:</em>

<em>            ship_weights = []</em>

<em>            for k in j:</em>

<em>                ship_weights.append(cows[k])</em>

<em>                #print(ship_weights)</em>

<em>            ship.append(sum(ship_weights))</em>

<em>            #print(ship)</em>

<em>        if all(d <= limit for d in ship):</em>

<em>            possibilities.append(i)</em>

<em>      pruned_possibilities = []</em>

<em>    for k in possibilities:</em>

<em>        if k not in pruned_possibilities:</em>

<em>            pruned_possibilities.append(k)</em>

<em>    # now find the minimum list length:</em>

<em>    min_list_len = min(map(len, pruned_possibilities))</em>

<em>    for l in pruned_possibilities:</em>

<em>        if len(l) == min_list_len:</em>

<em>            return l</em>

<em>       </em>

<em>def compare_cow_transport_algorithms():</em>

<em>       greedy_start = time.time()</em>

<em>    greedy_results = greedy_cow_transport(cows, limit = 10)</em>

<em>    greedy_end = time.time()</em>

<em>    print('Greedy Algorithm time:', greedy_end -greedy_start)</em>

<em>    brute_force_start = time.time()</em>

<em>    brute_force_results = brute_force_cow_transport(cows, limit = 10)</em>

<em>    brute_force_end = time.time()</em>

<em>    print('Brute force time:', brute_force_end - brute_force_start)</em>

<em>    print('Greedy Algorithm results:', greedy_results)</em>

<em>    print('Number of trips returned by Greedy Algorithm:', len(greedy_results))</em>

<em>    print('Brute Force Algorithm results:', brute_force_results)</em>

<em>    print('Number of trips returned by Brute Force Algorithm:', len(brute_force_results))</em>

   

See more about python at brainly.com/question/13437928

#SPJ1

4 0
2 years ago
Please answer this a due tomorrow!!!
Masja [62]

Answer:

Please check the attachment.

Explanation:

The answers are self explanatory.

Download txt
4 0
3 years ago
How many Megabytes are there in a Gigabyte?
Tju [1.3M]
<span>
In quantities of data,
"kilo" = 2^10 = 1,024
"mega" = 2^20 = 1,048,576,
"giga" = 2^30 = 1,073,741,824 .

<span> <span /></span></span> <span>1 gig = 1,024 megs<span><span /></span></span>


7 0
4 years ago
What is Coding in Computer Science?​
motikmotik

Answer:

Computer Science

Explanation:

computer coding is the use of computer programming languages to give computers and machines a set of instructions on what actions to perform.

8 0
3 years ago
Read 2 more answers
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