We know: θ = ωo t + 1/2*α*t^2
so, α = 2*(θ - ωo t ) / t^2
Given: angular velocity = 96.0 rad/sectime = 7 secangular distance travelled = 28 rev
We know, In one revolution it completes 360 degrees = 6.28319 radangular distance traveled = 28 rev * 6.28319 rad
So, angular acceleration = 2*(28*6.28 - 96*7) / 7^2 = -20.25 rad/sec^2
Answer is: 354 days.
V = V₀ + g·t.
V - final velocity, V = 3·10⁸ m/s.
V₀ - initial velocity, V₀ = o, because spaceship is in rest.
t - t<span>ime, how long it takes for spaceship to move from one position to another.
</span>g - gravity, g = 9,8 m/s².
t = V÷g = 3,06·10⁷s = 510204min = 88503,4hr = 354 days.
Answer:
the water level was shallow beach, then it rose to deep sea, then the water receded to a beach
A and D are possible usage of radioactive substances, given that the substances have appropriate half lives and levels of emission.
Answer:
1.14*10^-3m
Explanation:
We know that
Volume= mass/ density
But
Area x depth= mass/density
πr²*depth= mass/density
r²=m/πdp
So
r= √0.35/3.142*0.085*1000
r= 1.14*10^-3m