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stealth61 [152]
4 years ago
9

Magma that cools and crystallizes on Earth's surface forms 

Physics
2 answers:
Nostrana [21]4 years ago
6 0

The correct answer is:

D. Extrusive rocks.

The explanation:

when extrusive igneous rocks form when magma reaches the Earth's surface a volcano and cools quickly. Most extrusive (volcanic) rocks have small crystals. Examples include basalt, rhyolite, andesite, and obsidian.

KatRina [158]4 years ago
5 0
The answer is D. Extrusive igneous<span> rocks form when magma reaches the Earth's surface a volcano and cools down very quickly. This forms many small crystal on the rock.</span>
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Eating an orange enables a person to perform about 3.5x10^4 J of work. To what height does eating and orange enable a 55kg woman
crimeas [40]
Joules is a unit for work which may decomposed into N.m. Work is a quantity which is a product of force (in this case, the woman's weight) and the distance she has traveled. 
 
                                    W = F x d      ;    d = W / F

Substituting the given, 
  
                             d = (3.5 x 10^4 J) / (55 kg x 9.8 m/s²) = 64.94 m

Thus, the woman can climb up to 64.94 meters. 

3 0
3 years ago
Read 2 more answers
Why is the majority of Earth's freshwater not readily available for our use?
lara [203]
The answer is B. It is locked up in glaciers and ice caps.

Hope this helped. Good luck! Please give me a thanks and Brainliest.
8 0
4 years ago
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Inside a television picture tube there is a build-up of electrons (charge of 1.602 × 10^–19 C) with an average spacing of 38.0 n
Brut [27]
The magnitude of electric field is produced by the electrons at a certain distance.

E = kQ/r²

where: 
E = electric field produced
Q = charge
r = distance
k = Coulomb Law constant 9 x10^9<span> N. m</span>2<span> / C</span><span>2

Given are the following:
Q = </span><span>1.602 × 10^–19 C
</span><span>r = 38 x 10^-9 m

Substitue the given:
E = </span>\frac{( 1.602 x 10^{-19} )( 9.0x10_{9} )}{(38x10^{-9}) ^{2} }

E = 998.476 kN/C


8 0
3 years ago
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Suppose you had the same laser and diffraction grating from the previous question but now you had a flat detection screen. You w
kolezko [41]

Answer:

measuring the zero intensity point, we can deduce the movement of the screen.

The distance from the center of the pattern to the first zero is proportional to the distance to the screen,

Explanation:

The expression for the diffraction phenomenon is

           a sin θ = m λ

for the case of destructive interference. In general the detection screen is quite far from the grid, let's use trigonometry to find the angles

           tan θ = y / L

     

in these experiments the angles are small

          tan θ = sin θ / cos θ = sin θ

          sunt θ = y / L

we substitute

          a \frac{y}{L}= m  λ

           y = m L λ / a

therefore, by carefully measuring the zero intensity point, we can deduce the movement of the screen.

 

The distance from the center of the pattern to the first zero is proportional to the distance to the screen, so you can know where the displacement occurs, it should be clarified that these displacements are very small so the measurement system must be capable To measure quantities on the order of hundredths of a millimeter, a micrometer screw could be used.

4 0
3 years ago
To calculate the change in kinetic energy, you must know the force as a function of _______. The work done by the force causes t
aliya0001 [1]

To calculate the change in kinetic energy, you must know the force as a function of position. The work done by the force causes the kinetic energy change

Explanation:

The work-energy theorem states that the change in kinetic enegy of an object is equal to the work done on the object:

\Delta E_k = W

where the work done is the integral of the force over the position of the object:

W=\int F(x) dx

As we see from the formula, the magnitude of the force F(x) can be dependent from the position of the object, therefore in order to solve correctly the integral and find the work done on the object, it is required to know the behaviour of the force as a function of the position, x.

6 0
3 years ago
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