Using the law of sines, we get sin(B)/b = sin(C)/c sin(18)/7 = sin(C)/11 0.0441452849107 = sin(C)/11 11*0.0441452849107 = sin(C) 0.4855981340177 = sin(C) sin(C) = 0.4855981340177 C = arcsin(0.4855981340177) or C = 180-arcsin(0.4855981340177) C = 29.0516679549861 or C = 150.948332045013 There are two possibilities for angle C because of something like sin(30) = sin(150) = 1/2 = 0.5
Those approximate values of C round to C = 29.05 and C = 150.95
If C = 29.05, then angle A is A = 180-B-C A = 180-18-29.05 A = 132.95 Making this triangle possible since angle A is a positive number
If C = 150.95, then angle A is A = 180-B-C A = 180-18-150.95 A = 11.05 making this triangle possible since angle A is a positive number
There are two distinct triangles that can be formed. One triangle is with the angles: A = 132.95, B = 18, C = 29.05 The other triangle is with the angles: A = 11.05, B = 18, C = 150.95 The decimal values are approximate
