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3 years ago

14. Find the total volume of the solid below. 6 cm 6 15 cm 22 cm 13 cm 17 cm

Mathematics

1 answer:

Blizzard [7]3 years ago

4 0

Answer:

79 cm

Step-by-step explanation:

add them together

sorry I am spelling this because it had to be 20 letters long

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A company makes cones out of solid foam. Each cone has height of 12 inches, and it’s base has radius of 1.5 inches. How much foa

balu736 [363]

Answer:

The height of the cone-shaped cup is 6 inches and the diameter at the top is 3 inches. What is ... Both cones and cylinders have circular bases.

Step-by-step explanation:

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3 years ago

The square root of -108

Elan Coil [88]

Because the number you provided is negative, we won't get a real answer instead a complex answer.

Now simplify the square root.

To simplify a square root, find two factors where one of the factors is a perfect square.

$\sqrt{-108} = \sqrt{(-3)(36)} = \sqrt{-3}\sqrt{36} = 6\sqrt{(-1)(3)} = 6\sqrt{(-1)}\sqrt{3} = 6i\sqrt{3}$

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3 years ago

What is ml if the volume is 48cm cubic

Hoochie [10]

Answer:

48 ml

Step-by-step explanation:

1 cubic centimeter is equal to 1 milliliter

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3 years ago

Read 2 more answers

What is 25-3x=10 broken down

Tema [17]

Answer:

The answer is x = 5

Step-by-step explanation:

The given equation is

25 - 3x = 10

So when we break down this equation, we will have the value of x. Now breaking down the equation and moving variables to the correct positions.

25 - 3x = 10

Moving -3x and 10 to the other sides

25 - 10 = 3x

3x = 25 - 10

3x = 15

Now dividing both sides with 3, we get the following answer

3x/3 = 15/3

x = 5

Breaking down the equation gives us the value of x, i-e 5

5 0

4 years ago

We need to optimize f(x, y, z) = x + 2y subject to the constraints g(x, y, z) = x + y + z = 8 and h(x, y, z) = y2 + z2 = 4. To f

Evgesh-ka [11]

The Lagrangian is

$L(x,y,z,\lambda,\mu)=x+2y+\lambda(x+y+z-8)+\mu(y^2+z^2-4)$

with critical points where the partial derivatives vanish:

$L_x=1+\lambda=0\implies\lambda=-1$

$L_y=2+\lambda+2\mu y=0\implies\mu=-\dfrac1{2y}$

$L_z=\lambda+2\mu z=0\implies\mu=\dfrac1{2z}$

$L_\lambda=x+y+z-8=0$

$L_\mu=y^2+z^2-4=0$

The second and third equations tell us $z=-y$ , so that in the last equation we find

$y^2+(-y)^2=2y^2=4\implies y=\pm\sqrt2\implies z=\mp\sqrt2$

and from the fourth equation we get

$x+y+z=x=8$

So we have two critical points, $(8,\sqrt2,-\sqrt2)$ and $(8,-\sqrt2,\sqrt2)$ , which give respective extreme values of $f(8,\sqrt2,-\sqrt2)=8+2\sqrt2$ (maximum) and $f(8,-\sqrt2,\sqrt2)=8-2\sqrt2$ (minimum).

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4 years ago