Let y = 12 e^2x
e^2x = y/12
Taking
[email protected]ln e^2x = ln (y/12)
2x = ln (y/12)
x = (1/2) ln (y / 12)
so the inverse h-1(x) = (1/2) ln ( x / 12)
Complete question
To find
, Beau found
and
. He said that since 5 is between 4 and 9,
, is between 2 and 3. Beau thinks a good estimate for
, is
Is his estimate high or low? How do you know?
Answer:
The estimation is high because 5 is very close to 4 so
will also be very close to
which is lower than the estimate
In order to get a good estimate
The first step is to choose a number between 2 and 3 let say 2.8 , 2,85 , 2.9 and the square them
i.e



From here we can see that
lies between 2.2 and 2.3 but is closer to 2.2
So a good estimate for
is 2.2
Step-by-step explanation:
The answer is
5q/2 or q×5/2
Answer:
7 units
Step-by-step explanation:

=7
Answer:
Pythagorean Theorem:
a^2 + b^2 = c^2
6^2 + b^2 = 12^2
36 + b^2 = 144
b^2 = 108
b = 10.4
Let me know if this helps!