We have that
(w^5*z^2)*(-9*w^2*z^<span><span>5)</span>
</span><span>Multiplying exponential expressions
we know that
</span>w^5<span> multiplied by </span>w^<span>2 = w</span>^<span>(5 + 2) = w</span>^7
and
z^2<span> multiplied by </span>z^<span>5 = z</span>^<span>(2 + 5) = z</span>^7
therefore
(w^5*z^2)*(-9*w^2*z^5) =-9*( w^7)*( z^7)
-9*( w^7)*( z^7)=-(3^2)*( w^7)*( z^7)
the answer is
-(3^2)*( w^7)*( z^7
Answer: uhhhhhh pass
Step-by-step explanation:
Answer:
1.) It's 20th century painting
2.) 0.5 probability
Step-by-step explanation:
If the universal = 60
We need to first get the value of X. That is,
x (x - 2) + x + 2x + 8 + 10 = 60
First open the bracket
x^2 - 2x + x + 2x + 8 + 10 = 60
x^2 + x + 18 = 60
x^2 + x - 42 = 0
Factorise the above equation
x^2 + 7x - 6x - 42 = 0
x (x + 7) -6(x + 7) = 0
x = 6 or - 7
Since x can't be negative, so we will ignore -7
The value for T = 6(6 - 2) = 6×4 = 24
The value for B = 2(6) + 8 = 12 + 8 = 20
If a painting is chosen from random,
If it's from 20th century, the probability will be 34/60 = 0.567
If it's from British painting, the probability will be 30/60 = 0.5
We can therefore conclude that it's from 20th century painting since it has higher value of probability.
The the probability of choosing a British painting will be 30/60 = 0.5
