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3 years ago

10

What are the factors of 12x^3y^3--24x^2y^3 Factor completely and show work.

2 answers:

Licemer1 [7]3 years ago

7 0

Answer:

3y/4x^2

Step-by-step explanation:

Fed [463]3 years ago

5 0

Already factored:

Factors of 12X^3y^3 - 24x^2y^3

Answer:

The Factors of 12 are: 1, 2, 3, 4, 6, 12

The factor pairs of 12 are:
1(12) = 12
2(6) = 12
3(4) = 12

Hope this helps.!!!

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2466/3 is equal to 822.

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If p is the hypothesis of a conditional statement and

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2 years ago

Choose the solution(s) of the following system of equations x2 + y2 = 6 x2 – y = 6

ElenaW [278]

<h2>Answer</h2>

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

Or as ordered pairs: $(\sqrt{6} ,0),(-\sqrt{6} ,0),(\sqrt{5} ,-1),(-\sqrt{5} ,-1)$

<h2>Explanation</h2>

Lets solve our system of equations step by step

$x^2+y^2=6$ equation (1)

$x^2-y=6$ equation (2)

1. Solve for $x^2$ in equation (2)

$x^2-y=6$

$x^2=6+y$ equation (3)

2. Replace equation (3) in equation (1) and solve for $y$

$x^2+y^2=6$

$6+y+y^2=6$

$y^2+y=0$

$y(y+1)=0$

$y=0$ or $y=-1$

3. Replace the values of $y$ in equation (3) and solve for $x$

- For $y=0$

$x^2=6+y$

$x^2=6$

$x=\sqrt{6}$ or $x=-\sqrt{6}$

- For $y=-1$

$x^2=6+y$

$x^2=6-1$

$x^2=5$

$x=\sqrt{5}$ or $x=-\sqrt{5}$

So, the solutions of our system of equation are:

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

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3 years ago

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arlik [135]

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<h2>ANSWER</h2>

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or

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