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swat32
3 years ago
10

An area rug has an area of 48 square feet.Two similar rugs have areas of 108 square feet and 192 square feet. In each rug, the l

ength is 1 1/3 times the width. Which of the following could be the dimensions of one of the area rugs?
Mathematics
1 answer:
Svetllana [295]3 years ago
4 0
For area A, the width will be √(3A/4), so for the three rugs, the widths are 6 ft, 9 ft, 12 ft. Corresponding lengths are 4/3 times that, so are 8 ft, 12 ft, 16 ft.

The rug dimensions are
.. 6 ft x 8 ft
.. 9 ft x 12 ft
.. 12 ft x 16 ft

Pick the one(s) that are on your list.
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Which algebraic expression is equivalent to the expression below?
Vera_Pavlovna [14]
<h3><u>Answer:</u></h3>

=11n+18

<h3><u>Step-by-step explanation:</u></h3>

3n+13+5+8n

<h3><u>Combine Like Terms:</u></h3>

=3n+13+5+8n

=(3n+8n)+(13+5)

=11n+18

6 0
3 years ago
What is the product of 7/8 x 4/7
DIA [1.3K]

Answer:

1/2

Step-by-step explanation:

7x4= 28

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simplify: 28/56=1/2

8 0
2 years ago
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4 0
3 years ago
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Hi guys, can anyone help me with this triple integral? Many thanks:)
Crank

Another triple integral.  We're integrating over the interior of the sphere

x^2+y^2+z^2=2^2

Let's do the outer integral over z.   z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

y^2=4-x^2-z^2

x is the inner integral so at this point we conservatively say its zero.  That means y goes from -\sqrt{4-z^2} and +\sqrt{4-z^2}

Similarly the inner integral x goes between \pm-\sqrt{4-y^2-z^2}

So we rewrite the integral

\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz

Let's work on the inner one,

\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz

There's no z in the integrand, so we treat it as a constant.

=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}

So the middle integral is

\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy  

I gotta go so I'll stop here, sorry.

7 0
3 years ago
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There is a total of $35,000 worth of prizes being given out for 5,000 tickets.  We can find the expected value for each ticket by dividing 35,000/5,000.  This equals $7.00.
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