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mario62 [17]
3 years ago
9

there are 342 seats in the Jefferson middle school auditorium. There are 75 seats being used by teachers. Students are using 2/3

of the seats. How many are not being used in the auditorium?
Mathematics
2 answers:
V125BC [204]3 years ago
8 0

Answer:

267 i think. I might have counted wrong



irinina [24]3 years ago
3 0

Answer:

39 seats are not being used in the auditorium.

Step-by-step explanation:

We have bee given the total number of seats:

In middle school auditorium are 342

Seats used  by teachers are 75

And seats used by students are \frac{2}{3}\text{of the seats}

And \frac{2}{3}\cdot 342=228seats used  by students

That means  228+75=303 seats are used

We need to calculate seats not being used which is equal to

Total seats minus  seats used =342-303 =39 seats remain unused.

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The population of a certain community is known to increase at a rate proportional to the number of people present at time t. If
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Answer:

t=7.85 years

Step-by-step explanation:

We can write this rate as an ordinary differential equation.

\frac{dP}{dt}=aP

Where a is proportional constant, P the population variable, and t the time.

\frac{dP}{P}=adt

Integrating each side of the equation.

\int \frac{dP}{P}=\int adt

ln(P)=at+c

P=e^{at+c}

P=e^{c}e^{at}=Ce^{at}

To find C we need to use the initial condiction, it means evaluae P at t=0.

P_{0}=Ce^{0}=C

P=P_{0}e^{at}

Now, we use the sentence  the population has doubled in 5 years.

2P_{0}=P_{0}e^{a5}

We can find "a" in this condition.

2=e^{a5}

ln(2)=a5

a=\frac{ln(2)}{5}

a=0.14

Finally, let's find how long will it take to triple.

3P_{0}=P_{0}e^{0.14t}

3=e^{0.14t}

t=\frac{ln(3)}{0.14}

t=7.85 years

I hope it helps you!

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Step-by-step explanation:

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Anduin casts a variety of healing spells. The number of health points that each of his healing spells restores
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If the function f (x) has a domain of (a,b] and a range of [c,d), then what is the domain and range of g (x) = m × f (x) + n?
xz_007 [3.2K]
<h3>Answer: Choice A</h3>

Domain = (a,b]

Range = [mc + n,md + n)

==============================================

Explanation:

The domain stays the same because we still have to go through f(x) as our first hurdle in order to get g(x).

Think of it like having 2 doors. The first door is f(x) and the second is g(x). The fact g(x) is dependent on f(x) means that whatever input restrictions are on f, also apply on g as well. So going back to the "2 doors" example, we could have a problem like trying to move a piece of furniture through them and we'd have to be concerned about the f(x) door.

-------------------

The range will be different however. The smallest value in the range of f(x) is y = c as it is the left endpoint. So the smallest f(x) can be is c. This means the smallest g(x) can be is...

g(x) = m*f(x) + n

g(x) = m*c + n

All we're doing is replacing f with c.

So that means mc+n is the starting point of the range for g(x).

The ending point of the range is md+n for similar reasons. Instead of 'c', we're dealing with 'd' this time. The curved parenthesis says we don't actually include this value in the range. A square bracket means include that value.

6 0
3 years ago
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