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3 years ago

7

A biker travels at a rate of 20 miles per hour. Calculate

2 answers:

Leona [35]3 years ago

7 0

Answer:

60

Step-by-step explanation:

20x3

kow [346]3 years ago

3 0

Answer:

60 miles

Step-by-step explanation:

20 miles times 3

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Juan got on an elevator at the middle floor of a building, went up 4 floors, down 3 floors, up one floor, down 9 floors, where h

xenn [34]

There are 14 floors in the building, because since Juan went up 4 floors, down 3 floors, and up one floor; so we know that he is 2 floors above from where he originally started. Once he went down 9 floors he passed the starting point and went to the bottom of the building. So, the middle must have been the 7th floor. Once I knew that I multiplied 7*2 and it got me 14. So in total there are 14 floors. I hope this helped ^^

5 0

3 years ago

F(x)=-x^3-x^2+1 what is f(-1)

xxMikexx [17]

-1^3 - -1^2 +1= -1. ...........

8 0

3 years ago

Carlos dropped the phone he had received for his birthday and broke the screen. He knows he has to pay for the replacement himse

NeX [460]

Answer:

you would want B

Step-by-step explanation:

why because if you get a discount you would be able to have to not pay as much as if you dont get a discount.

7 0

3 years ago

Mathematically verify the outlier(s) in the data set using the 1.5 rule.

statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

$Q_1=\dfrac{11+13}{2}$

$Q_1=\dfrac{24}{2}$

$Q_1=12$

And

$Q_3=\dfrac{16+16}{2}$

$Q_3=\dfrac{32}{2}$

$Q_3=16$

The interquartile range is:

$IQR=Q_3-Q_1$

$IQR=16-12$

$IQR=4$

The data values lies outside the interval $[Q_1-1.5IQR,Q_3+1.5IQR]$ are known as outliers.

$[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]$

$[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]$

$[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]$

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

3 0

3 years ago

How do i do this? it doesn't make sense

Genrish500 [490]

Answer:

The answer is B. 581/90

Step-by-step explanation:

just divide 581 by 90 and you'll find that it is equivelent to 6.4<u>5</u>

<u />

Hope that helps!

5 0

2 years ago

Read 2 more answers