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3 years ago

11

Through (-1,-4), parallel to y=7x-4

1 answer:

sweet [91]3 years ago

7 0

Y=7x+3

They are parallel so the slope is the same and plug in the two coordinates to get the y intercept. This gives you y=7x+3

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Please help me? Show your work please! I give brainiest! (Or whatever it’s called :) )

azamat

You need to find the hypotenuse of the right triangle.

4² + 9² = c²
16 + 81 = c²
97 = c²
9.85 = c

There are 5,280 ft in a mile.
Multiply 9.85 by 5,280.

9.85 × 5,280 = 52,008
Multiply 52,008 by 110.

52,008 × 110 = <span>5,720,880

The estimated cost for constructing the street would be $</span>5,720,880.

8 0

3 years ago

One of the giraffes, Bernard, is sick. Last week he weighed 2,490 pounds. This week he weighs 2,312 pounds. If w represents the

victus00 [196]

Answer:

$w+2,312=2,490$

$w=178\ pounds$

Step-by-step explanation:

Let

w ----> the amount of weight lost in pounds

we know that

The amount of weight Bernard lost plus the weight of this week must be equal to the weight of the last week

so

The linear equation that represent this situation is

$w+2,312=2,490$

solve for w

subtract 2,312 both sides

$w=2,490- 2,312=178\ pounds$

4 0

3 years ago

Read 2 more answers

I'm not understanding this can you help me

hoa [83]

Answer:

gawin mo pag isipan mo wag puro brainly

3 0

3 years ago

Read 2 more answers

Futhe Mathematics<br><img src="https://tex.z-dn.net/?f=%28Cos%20%7B%7D%5E%7B4%7Dt%20-Sin%20%7B%7D%5E%7B4%7Dt%20%29%20%20%5Cdiv%2

Nastasia [14]

Answer:

cos2t/cos²t

Step-by-step explanation:

Here the given trigonometric expression to us is ,

$\longrightarrow \dfrac{cos^4t - sin^4t }{cos^2t }$

We can write the numerator as ,

$\longrightarrow \dfrac{ (cos^2t)^2-(sin^2t)^2}{cos^2t }$

Recall the identity ,

$\longrightarrow (a-b)(a+b)=a^2-b^2$

Using this we have ,

$\longrightarrow \dfrac{(cos^2t + sin^2t)(cos^2t-sin^2t)}{cos^2t}$

Again , as we know that ,

$\longrightarrow sin^2\phi + cos^2\phi = 1$

Therefore we can rewrite it as ,

$\longrightarrow \dfrac{1(cos^2t - sin^2t)}{cos^2t}$

Again using the first identity mentioned above ,

$\longrightarrow \underline{\underline{\dfrac{(cost + sint )(cost - sint)}{cos^2t}}}$

Or else we can also write it using ,

$\longrightarrow cos2\phi = cos^2\phi - sin^2\phi$

Therefore ,

$\longrightarrow \underline{\underline{\dfrac{cos2t}{cos^2t}}}$

And we are done !

$\rule{200}{4}$

Additional info :-

<em>D</em><em>e</em><em>r</em><em>i</em><em>v</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>o</em><em>f</em><em> </em><em>c</em><em>o</em><em>s</em><em>²</em><em>x</em><em> </em><em>-</em><em> </em><em>s</em><em>i</em><em>n</em><em>²</em><em>x</em><em> </em><em>=</em><em> </em><em>c</em><em>o</em><em>s</em><em>2</em><em>x</em><em> </em><em>:</em><em>-</em>

We can rewrite cos 2x as ,

$\longrightarrow cos(x + x )$

As we know that ,

$\longrightarrow cos(y + z )= cosy.cosz - siny.sinz$

So that ,

$\longrightarrow cos(x+x) = cos(x).cos(x) - sin(x)sin(x)$

On simplifying,

$\longrightarrow cos(x+x) = cos^2x - sin^2x$

Hence,

$\longrightarrow\underline{\underline{cos (2x) = cos^2x - sin^2x }}$

$\rule{200}{4}$

7 0

2 years ago

Solve the problem:

Over [174]

Answer:

Step-by-step explanation:

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4 0

3 years ago