Answer:
String word = "George slew the dragon";
int pos = word.indexOf("dr");
String drWord = word.substring(pos, pos+4);
System.out.println(drWord);
Explanation:
Assuming dr is always there, we don't have to check the validity of 'pos'. Normally, you would!
Answer:
Never heard of that lol
Answer:
#include <stdio.h>
int fib(int n) {
if (n <= 0) {
return 0;
}
if (n <= 2) {
return 1;
}
return fib(n-1) + fib(n-2);
}
int main(void) {
for(int nr=0; nr<=20; nr++)
printf("Fibonacci %d is %d\n", nr, fib(nr) );
return 0;
}
Explanation:
The code is a literal translation of the definition using a recursive function.
The recursive function is not per se a very efficient one.
Answer: 83.17
Explanation:
By definition, the dB is an adimensional unit, used to simplify calculations when numbers are either too big or too small, specially in telecommunications.
It applies specifically to power, and it is defined as follows:
P (dB) = 10 log₁₀ P₁ / P₂
Usually P₂ is a reference, for instance, if P₂ = 1 mW, dB is called as dBm (dB referred to 1 mW), but it is always adimensional.
In our question, we know that we have a numerical ratio, that is expressed in dB as 19.2 dB.
Applying the dB definition, we can write the following:
10 log₁₀ X = 19.2 ⇒ log₁₀ X = 19.2 / 10 = 1.92
Solving the logarithmic equation, we can compute X as follows:
X = 10^1.92 = 83.17
X = 83.17
Answer:
E-book : online edition of a new novel .
e-zine:online issue of today’s newspaper.
Online reference: online encyclopedia
blog: online website that posts restaurants reviews
Explanation:
Are you doing edge?
Also pleaseeeeeeeeeeeeeeeeeee mark me brainliest.