Answer:
321354345
Step-by-step explanation:
The seven is in the hundredths place.
Total possible outcomes = 36
Total possible outcomes with sum equal to 4 = 3
{1, 3} {2, 2}, (3, 1}
P(sum equal to 4) = 3/36 = 1/12
If you throw it 1000 times,
Number of times expected to have a sum of 4 = 1/12 x 1000 = 83 times
Answer: About 83 times
(2×12×200.50)÷(2,500×25) *100=7.7%
Answer:
hahahahahha
Step-by-step explanation:
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