<span><span><span>(3x−2)/</span><span>(x−1<span>)^2</span></span></span>=<span>A/(<span>x−1) </span></span>+ <span><span>B/x</span><span>(x−1<span>)^2
</span></span></span> =[<span><span>A(x−1)+Bx</span><span>(x−1<span>)] / 2</span></span></span></span>
3x-2=A(x-1)+Bx
3x-2=x(A+B)-A
A+B=3
-A=-2=>A=2
A+B=3=>2+B=3=>B=1
lets check our partial fraction
we have
<span><span><span>2/(<span>x−1) </span></span>+ <span>x/<span>(x−1<span>)^2 </span></span></span>= [<span><span>2(x−1)+x] / </span><span>(x−1<span>)^2
</span></span></span> =(<span><span>3x−2) / </span><span>(x−1<span>)^2</span></span></span></span></span>
<em><u>Areyy, don't scare ppls, they'll refuse to answer</u></em>
Step-by-step explanation:
2nd option is ur answer hope u get it
Let's solve your equation step-by-step.<span><span><span>−<span>7<span>(<span>x−4</span>)</span></span></span>+<span>8x</span></span>=<span>12+14
</span></span>Step 1: Simplify both sides of the equation.<span><span><span>−<span>7<span>(<span>x−4</span>)</span></span></span>+<span>8x</span></span>=<span>12+14
</span></span><span>Simplify: (Show steps)</span><span><span>x+28</span>=26
</span>Step 2: Subtract 28 from both sides.<span><span><span>x+28</span>−28</span>=<span>26−28
</span></span><span>x=<span>−<span>2</span></span></span>