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3 years ago

Which equation matches the graph below?

1 answer:

6 0

Answer:Given that the graph shows tha the functión at x = 0 is below the y-axis, the constant term of the function has to be negative. This leaves us two possibilities:

y = 8x^2 + 2x - 5 and y = 2x^2 + 8x - 5

To try to discard one of them, let us use the vertex, which is at x = -2.

With y = 8x^2 + 2x - 5, you get y = 8(-2)^2 + 2(-2) - 5 = 32 - 4 - 5 = 23 , which is not the y-coordinate of the vertex of the curve of the graph.

Test the other equation, y = 2x^2 + 8x - 5 = 2(-2)^2 + 8(-2) - 5 = 8 - 16 - 5 = -13, which is exactly the y-coordinate of the function graphed.

Step-by-step explanation:

You might be interested in

10x+36-38x-47 I don't understand this question i am so confused please explain i would be really thankful.

Lelechka [254]

-28x-11

Step-by-step explanation:

10x-38x=-28x

+36-47=-11

so the answer is -28x-11

8 0

2 years ago

Scott was considering the equation 5 - x = 12. He said, "That seems

den301095 [7]

Answer:

-7

Step-by-step explanation:

$5 - x = 12 \\ 5 - 12 = x \\ - 7 = x$

it is possible because x is just a letter representing the unknown nos

7 0

2 years ago

In 2018, the population will grow over 700,000.The population of a city in 2010 was 450,000 and was growing at a rate of 5% per

Firlakuza [10]

Answer:

The year is 2020.

Step-by-step explanation:

Let the number of years passed since 2010 to reach population more than 7000000 be 'x'.

Given:

Initial population is, $P_0=450,000$

Growth rate is, $r=5\%=0.05$

Final population is, $P=700,000$

A population growth is an exponential growth and is modeled by the following function:

$P=P_0(1+r)^x$

Taking log on both sides, we get:

$\log(P)=\log(P_0(1+r)^x)\\\log P=\log P_0+x\log (1+r)\\x\log (1+r)=\log P-\log P_0\\x\log(1+r)=\log(\frac{P}{P_0})\\x=\frac{\log(\frac{P}{P_0})}{\log(1+r)}$

Plug in all the given values and solve for 'x'.

$x=\frac{\log(\frac{700,000}{450,000})}{\log(1+0.05)}\\x=\frac{0.192}{0.021}=9.13\approx 10$

So, for $x > 9.13$ , the population is over 700,000. Therefore, from the tenth year after 2010, the population will be over 700,000.

Therefore, the tenth year after 2010 is 2020.

8 0

2 years ago

Please explain the how you got the answers thanks asap

stich3 [128]

Answer:

a) 90 stamps

b) 108 stamps

c) 333 stamps

Step-by-step explanation:

Whenever you have ratios, just treat them like you would a fraction! For example, a ratio of 1:2 can also look like 1/2!

In this context, you have a ratio of 1:1.5 that represents the ratio of Canadian stamps to stamps from the rest of the world. You can set up two fractions and set them equal to each other in order to solve for the unknown number of Canadian stamps. 1/1.5 is representative of Canada/rest of world. So is x/135, because you are solving for the actual number of Canadian stamps and you already know how many stamps you have from the rest of the world. Set 1/1.5 equal to x/135, and solve for x by cross multiplying. You'll end up with 90.

Solve using the same method for the US! This will look like 1.2/1.5 = x/135. Solve for x, and get 108!

Now, simply add all your stamps together: 90 + 108 + 135. This gets you a total of 333 stamps!

5 0

3 years ago

maria works as a florist and worked for 8 hours last week and earned 98$ at that rate how much will she earn this weekend if she

olga_2 [115]

$171.50

$98 ÷ 8 = $12.25 per hour

$12.25 x 14 = $171.50

7 0

3 years ago

Read 2 more answers