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Fittoniya [83]
3 years ago
9

What percent of 2000 is 204

Mathematics
1 answer:
Darina [25.2K]3 years ago
3 0
204 is 10.2% of 2000

Working Out 

204/2000 x 100 = 10.2%
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17. ralph is 3 times as old as sarah. in 4 years ralph will only be twice as old as sara will be then. find ralph’s age now.
spin [16.1K]

Answer:

Sara is now 4, will be 8 in 4 years. Ralph is now 12, will be 16 in 4 years.

7 0
3 years ago
A student translated the phrase below into an algebraic expression, and then evaluated it for g = one-fourth. Is the student's w
iragen [17]

Answer:

The correct evaluation is 1 1/3 (one and one-third) and not 16 and one-third

Step-by-step explanation:

The student was wrong in his evaluation because the correct result should be 1 1/3 (one and one-third) and not 16 and one-third

The expression '1/3 more than the product of four and a number' means

(4g + 1/3)

Evaluating the expression when g = 1/4

You will have

4×1/4 + 1/3

= 1/1 + 1/3

Find the LCM of 1 and 3 and add

= (3+1)/3

=4/3

= 1 1/3

The correct evaluation is 1 1/3 (one and one-third) and not 16 and one-third

6 0
3 years ago
Read 2 more answers
In ΔABC, point M is the midpoint of side AB and point D is the midpoint of segment MC. Prove that the area of ΔADC= the area of
Anna11 [10]
A line segment from a vertex to the midpoint of the opposite side is a "median". A median divides the area of the triangle in half, as it divides the base in half without changing the altitude.
AAMC is half AABC. AADC is half AAMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
ABMC is half AABC. ABMD is half ABMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
Then, AADC = 1/4 AABC = ABMC, so AADC = ABMC by the transitive property of equality.
8 0
3 years ago
If p(a) = 0.50, p(b) = 0.60, and p(a intersection
bogdanovich [222]
Use the identity P(A ∪ B) = P(A)+P(B)-P(A ∩ B)

P(A)=0.50
P(B)=0.60
P(A ∪ B) = 0.30
=>
P(A ∪ B) = P(A)+P(B)-P(A ∩ B)
=(0.50+0.60)-0.30
=0.80
5 0
3 years ago
Nonsense will be reported!!​
Pavlova-9 [17]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

The required additional information required to prove the Triangles congruent are :

\qquad \sf  \dashrightarrow \: 1. \: X V= FD

The Triangles will be congruent by HL congruency.

\qquad \sf  \dashrightarrow \: 2. \: MH = MI

The Triangles are congruent by LL congruency.

\qquad \sf  \dashrightarrow \: 3. \:  \angle EDC =  \angle VUC

The Triangles are congruent by HA congruency.

\qquad \sf  \dashrightarrow \: 4. \:  \angle J  =  \angle C

The Triangles are congruent by LA congruency.

5 0
2 years ago
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