Answer:
Northern Hemisphere
Explanation:
The latitude of Bhutan is 27.5142° N, placing the country in the northern hemisphere above the equator
Answer:
4.17 m/s²
Explanation:
We are told the reaction time is 0.2 s. Now, during this reaction time the car is going to travel an additional distance of
: x = u × t = 40 × 0.2 = 8 m
where u is the initial velocity of the car which is 40.0 m/s.
We are told that he had 200 m to stop before applying brakes. Thus, after applying brakes, he now has a distance to cover of; s = 200 - 8 = 192 m
Since vehicle is coming to rest acceleration would be negative, thus using Newton's equation of motion, we have;
v
² = u² - 2as
v = 0 m/s since it's coming to rest
u = 40 m/s
s = 192 m
Thus;
0² = 40² - 2(a)(192)
0² = 1600 - 384a
a = 1600/384
a = 4.17 m/s²
Answer:
1.76km
Explanation:
Here,
1mi = 1.6km
1.10 miles = 1.6 x 1.10 km
= 1.76 km
Answer:
Explanation:
Kinetic energy can be found using the following formula:
where <em>m </em>is the mass and <em>v</em> is the velocity.
The mass of the ball is 0.5 kilograms and the velocity is 15 meters per second
Substitute the values into the formula.
First, evaluate the exponent.
- (15 m/s)²= (15 m/s) * (15 m/s) = 225 m²/s²
Multiply 0.5 kg by 225 m²/s²
Multiply 112 kg*m²/s² by 1/2, or divide by 2.
- 1 kg*m²/s² is equal to 1 Joule
- Therefore, our answer of 56.25 kg*m²/s² is equal to 56.25 Joules.
The kinetic energy of the ball is <u>56.25 Joules</u>
Answer:
A. 28.42 m/s
B. 41.21 m.
Explanation:
A. Determination of the initial velocity of the ball:
Time (t) to reach the maximum height = 2.9 s
Final velocity (v) = 0 (at maximum height)
Acceleration due to gravity (g) = –9.8 m/s² (since the ball is going against gravity)
Initial velocity (u) =?
Thus, we can obtain the initial velocity of the ball as follow:
v = u + gt
0 = u + (–9.8 × 2.9)
0 = u – 28.42
Collect like terms
u = 0 + 28.42
u = 28.42 m/s
Therefore, the initial velocity of the ball is 28.42 m/s.
B. Determination of the maximum height reached.
Final velocity (v) = 0 (at maximum height)
Acceleration due to gravity (g) = –9.8 m/s² (since the ball is going against gravity)
Initial velocity (u) = 28.42 m/s.
Maximum height (h) =?
Thus, we can obtain the maximum height reached by the ball as follow:
v² = u² + 2gh
0² = 28.42² + (2 × –9.8 × h)
0 = 807.6964 + (–19.6h)
0 = 807.6964 – 19.6h
Collect like terms
0 – 807.6964 = – 19.6h
– 807.6964 = – 19.6h
Divide both side by – 19.6
h = –807.6964 / –19.6
h = 41.21 m
Therefore, the maximum height reached by the ball is 41.21 m