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Tamiku [17]
3 years ago
14

Use the discriminant to find all values of b for which the question has one real solution.

Mathematics
1 answer:
Arada [10]3 years ago
4 0
Use the formula 0 = b^2-4ac

0 = -b^2-4(2)(-9)

0 = -b^2+72

b^2 = 72

b = square root of 72

b = 2 real numbers
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Help please! show work thanks
Andre45 [30]
Answers
b = 2.77 m
A = 43.0°
C = 111.1°

cosine law to find b

b^2 = a^2 + c^2 -2ac \cos B \\ \\&#10;b = \sqrt{a^2 + c^2 -2ac \cos B} \\ \\&#10;b = \sqrt{4.33^2 + 5.92^2 - 2(4.33)(5.92) \cos 25.9} \\&#10;b = 2.7708\ m

b = 2.7708\ m

Find angle A with sine law

\displaystyle&#10;\frac{\sin A}{a} = \frac{\sin B}{b} \\ \\&#10;\sin A = \frac{a \sin B}{b} \\ \\&#10;A = \sin^{-1} \left[ \frac{a \sin B}{b}  \right] \\ \\&#10;A = \sin^{-1} \left[ \frac{4.33 \sin 25.9}{2.7708}  \right]  \\ \\&#10;A = 43.0467020

Find C with angles in triangle sum to 180

A + B + C = 180
C = 180 - A - B
C = 180 - 43.0467020 - 25.9
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6 0
3 years ago
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