Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M±
where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12±
=12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
Answer:
a = 
Step-by-step explanation:
Given
ga + q = r ( subtract q from both sides )
ga = r - q ( isolate a by dividing both sides by g )
a = 
Answer:
tem
Step-by-step explanation:
3+1=10
He paid ...
-- The cost of the lunches (100% = 1.00 of it)
-- 15% of the cost as a tip (15% = 0.15 of it)
-- 12% of the cost as sales tax (12% = 0.12 of it)
Total that he paid = (1.00 + 0.15 + 0.12) = 1.27 of $248.40
= $315.47 .
Trevor is one generous guy !