Answer:
a) 81.5%
b) 95%
c) 75%
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 266 days
Standard Deviation, σ = 15 days
We are given that the distribution of length of human pregnancies is a bell shaped distribution that is a normal distribution.
Formula:

a) P(between 236 and 281 days)

b) a) P(last between 236 and 296)

c) If the data is not normally distributed.
Then, according to Chebyshev's theorem, at least
data lies within k standard deviation of mean.
For k = 2

Atleast 75% of data lies within two standard deviation for a non normal data.
Thus, atleast 75% of pregnancies last between 236 and 296 days approximately.
50% or 1/2 of 4 is 2 50% or 1/2 of 6 is 3 so then just add them to the respective number since its going up by 50% or 2 in by 3 in \[\frac{ 6 }{ 9}\]
Answer:
y = mx + 1/2
Step-by-step explanation:
(x,y)
- Plot each point on a graph
- The line should go from the bottom left (-6,-10) to the top right (1,4)
- Count how many spaces are on the y-axis from -6 to 1 for numerator
- Count how many spaces are on the x-axis from -10 to 4 for denominator
- Positive slope
- Slope = 7/14
- Simplify to 1/2
Answer:
Step-by-step explanation:
∠4=∠1