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zhenek [66]
3 years ago
8

Solve for x. −4≥10−7x x≤2 x≥−2 x≤−2 x≥2

Mathematics
1 answer:
Anettt [7]3 years ago
4 0
The answer to ur question is x<2
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Cual es la expasion decimal de 13/7
OverLord2011 [107]

Answer:

1.8571428571428571428571428571429‬

Step-by-step explanation:

Just divided it. The answer will be given exactly. :)

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3 years ago
Please help!!!!!!!!!!!
Temka [501]

9514 1404 393

Answer:

  (d)  h = 2A/b

Step-by-step explanation:

Multiply both sides of the equation by the inverse of the coefficient of h.

  A = \dfrac{1}{2}bh=\dfrac{b}{2}\cdot h\\\\\dfrac{2}{b}\cdot A=h\\\\\boxed{h=\dfrac{2A}{b}}

4 0
3 years ago
What is X if Y is 12.8 and Z is 16 in the right triangle below?
Natalija [7]

Answer:

Im 90% sure its H.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A study of 25 graduates of 4-year public colleges revealed the mean amount owed by a student in student loans was $55,051. The s
Harman [31]

Answer:

Step 1

The data represent amount.

A 90% confidence interval for the population mean is,

First, compute t-critical value then find confidence interval.

The t critical value for the 90% confidence interval is,

The sample size is small and two-tailed test. Look in the column headed and the row headed in the t distribution table by using degree of freedom is,

The t critical value for the 90% confidence interval is 1.711.

A 90% confidence interval for the population mean is .

Step 2

It is reasonable to conclude that mean of the population is actually $55000 due to a 90% confidence intrerval for population mean is between $52461.23 and $57640.77 does include $55000.

The data represent amount.

A 90% confidence interval for the population mean is,

First, compute t-critical value then find confidence interval.

The t critical value for the 90% confidence interval is,

The sample size is small and two-tailed test. Look in the column headed and the row headed in the t distribution table by using degree of freedom is,

The t critical value for the 90% confidence interval is 1.711.

A 90% confidence interval for the population mean is .

It is reasonable to conclude that mean of the population is actually $55000 due to a 90% confidence intrerval for population mean is between $52461.23 and $57640.77 does include $55000.

5 0
2 years ago
URGENT PLEASE HELP!!!
Ira Lisetskai [31]

Answer:

1) -17x-9

Step-by-step explanation:

1)

(-2x^3+x-5)+(x^3-3x-4)

Combine like terms using P.E.M.D.A.S:

(-2x^3+x-5)+(x^3-3x-4)

(-9x-5)+(-8x-4)

Combine like terms:

(-2x^3+x-5)+(x^3-3x-4)

(-9x-5)+(-8x-4)

-17x-9

I hope this helps a bit!☺

8 0
2 years ago
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