A kite is stuck in a 36-ft tree. If the angle of elevation from the kite and the ground is 12, find the length of the kite.
1 answer:
Answer:
173.15 ft.
Step-by-step explanation:
Please find the attachment.
Let L be the length of kite.
We have been given that a kite is stuck in 36-ft tree. The angle of elevation from the kite and the ground is 12.
We can see from our attachment that kite and tree form a right triangle. height of tree is opposite of angle of elevation and length of kite is hypotenuse.
Since we know that Sine relates the opposite and hypotenuse of a right triangle, so we will use sine to find the length of kite.
Therefore, the length of kite is 173.15 ft.
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Answer:
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Step-by-step explanation:
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(-4, -1/2)
Answer:
a)The expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b)0.6004
c)19.607
Step-by-step explanation:
Let X denotes the number of fragments in 200 gm chocolate bar with expected number of fragments 10.2
X ~ Poisson(A) where
a)We are supposed to find the expected number of insect fragments in 1/4 of a 200-gram chocolate bar
50 grams of bar contains expected fragments = \lambda x = 0.051 \times 50=2.55
So, the expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b) Now we are supposed to find the probability that you have to eat more than 10 grams of chocolate bar before ending your first fragment
Let X denotes the number of grams to be eaten before another fragment is detected.
c)The expected number of grams to be eaten before encountering the first fragments :
s