Answer:
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Answer:
r = 225 Mil/h speed of the airplane in still air
Step-by-step explanation:
Then:
d is traveled distance and r the speed of the airplane in still air
so the first equation is for a 4 hours trip
as d = v*t
d = 4 * ( r + 25) (1) the speed of tail wind (25 mil/h)
Second equation the trip back in 5 hours
d = 5 * ( r - 25 ) (2)
So we got a system of two equation and two unknown variables d and
r
We solve it by subtitution
from equation (1) d = 4r + 100
plugging in equation 2
4r + 100 = 5r - 125 ⇒ -r = -225 ⇒ r = 225 Mil/h
And distance is :
d = 4*r + 100 ⇒ d = 4 * ( 225) + 100
d = 900 + 100
d = 1000 miles
Answer:
6/25
Step-by-step explanation:
.24 = 24/100 = 6/25
Five squared with the little two and 2 because 5 Times 10 is 50 and five is prime so then from 10 and you get five and two and both five and two are prime
The first two numbers between 100 and 150 that have a HCF of 22 are 110 and 132
<h3>Highest common factors</h3>
The greatest common divisor of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.
According to the question, we are to find two numbers between 100 and
150 that have a HCF of 22.
In order to do that we will<u> multiply 22 by the values 5 and 6</u>
First number = 22 * 5 = 10
Second number = 22 * 6 = 132
Hence the first two numbers between 100 and 150 that have a HCF of 22 are 110 and 132
Learn more on HCF here; brainly.com/question/21504246
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