Answer: Ordinal 
Step-by-step explanation:
We know that the ordinal scale is a level of measurement which is used when we are ordering attributes according to their ranks or preferences. 
For example : In an exam we arrange position of students as :
First > Second > Third and so on.
Given : A group of women tried five brands of fingernail polish and ranked them according to preference. It means she is arranging the brands in an order .
Thus this is an ordinal level of measurement .
 
        
             
        
        
        
Answer:
1.) 48
2.) 65
3.) 36
Step-by-step explanation:
1.)     If the equation is 6(x-4) and x = 12, then all we have to do is plug in the value of x. When we plug in, all we do is substitute 12 for x because they mentioned in the question that x = 12. So, we end up getting 6(12 - 4). After solving this, we get 48.
2.)     This problem is a lot like the last problem. All we need to do is substitute /plug in the values of x and y into the equation, to get 4(4^2) - 35/7 - (8 + 14). After solving, we get 65.
3.) .     This problem, once again, is also a lot like the last problems. We need to substitute the value of x into the equation 8x+12. Since we know from the problem that x is 3, all we have to do is 8 * 3 + 12.
 
        
                    
             
        
        
        
Answer:
C  =  6
Step-by-step explanation:
Move all terms that don't contain  C  to the right side and solve.
 
        
                    
             
        
        
        
Answer:
1. Perpendicular
2. Isosceles
3. Never
Step-by-step explanation:
1. AC ⊥ BD because diameter of a square are perpendicular bisector of each other.
2. In Δ AOB , By using pythagoras : AB² = OA² + OB² .......( 1 )
In Δ COB , By using pythagoras : BC² = OC² + OB²  ..........( 2 )
But, OA = OC because both are radius of same circle
So, by using equations ( 1 ) and ( 2 ), We get AB = BC ≠ AC
⇒ ABC is a triangle having two equal sides so ABC is an isosceles triangle.
3. The side can never be equal to radius of circle because the side of the square will be chord for the circle and in a circle chord can never be equal to its radius