Evaluate the function f(x)=x^2-5x+ 5 at the given values of the independent variable and simplify
1 answer:
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Assuming you mean
first use chain rule on first part
derivitive of (x+1)⁵=5(x+1)⁴ times the derivitive of (x+1) which is 1
the first part is 5(x+1)⁴
derivitive of -5x is -5
derivitive of -2 is 0
we gots
f'(x)=5(x+1)⁴-5
find zeroes
0=5(x+1)⁴-5
5=5(x+1)⁴
1=(x+1)⁴
+/-1=x+1
-1+/-1=x
-2=x or 0=x
f'(x)=5(x+1)⁴-5
zeroes at x=-2 and x=0
first use chain rule on first part
derivitive of (x+1)⁵=5(x+1)⁴ times the derivitive of (x+1) which is 1
the first part is 5(x+1)⁴
derivitive of -5x is -5
derivitive of -2 is 0
we gots
f'(x)=5(x+1)⁴-5
find zeroes
0=5(x+1)⁴-5
5=5(x+1)⁴
1=(x+1)⁴
+/-1=x+1
-1+/-1=x
-2=x or 0=x
f'(x)=5(x+1)⁴-5
zeroes at x=-2 and x=0
Formula:
π(6)(8) + π(6)(6)
48π + 36π
84π
84( 3.14 )
Answer: 263.76 cm^2
IGNORE, IT IS WRONG
π(6)(8) + π(6)(6)
48π + 36π
84π
84( 3.14 )
Answer: 263.76 cm^2
IGNORE, IT IS WRONG
Graph each points:
f(x) = -13x + 1
when x = 0, y = 1
f(0) = -13(0) + 1
f(0) = 0 + 1
f(0) = 1
when x = 1, y = -14
f(1) = -13(1) + 1
f(1) = -13 + 1
f(1) = -14
when x = 2, y = -25
f(2) = -13(2) + 1
f(2) = -26 + 1
f(2) = -25
etc.
Graph each point and connect them.
