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gizmo_the_mogwai [7]
3 years ago
7

What are the Oder of operations

Mathematics
2 answers:
denis-greek [22]3 years ago
8 0

Answer:

The order of operations are : exponentiation and root extraction

multiplication and division

addition and subtraction

~Hope this answered your question :-) ~

Step-by-step explanation:

OLga [1]3 years ago
5 0

Answer:

PEMDAS

Step-by-step explanation:

P=Parentheses

E=Exponents

M=Multiplication

D=Division

A=Addition

S=Subtraction

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What is the product of 2x2 – 3xy + y2 and 2x – 4y?
dybincka [34]

Answer:

C. 4x^3 - 14x^2y + 14xy^2 - 4y^3

Step-by-step explanation:

Given:

Product of 2x^2 – 3xy + y^2 and 2x – 4y

Product means multiplication

(2x^2 – 3xy + y^2) (2x – 4y)

Open the bracket

= 4x^3 - 8x^2y - 6x^2y + 12xy^2 + 2xy^2 - 4y^3

Simplify the like terms

= 4x^3 - 14x^2y + 14xy^2 - 4y^3

The answer is

C. 4x^3 - 14x^2y + 14xy^2 - 4y^3

8 0
3 years ago
Write an equation of the cosine function with amplitude pi/2 and period 3
juin [17]

Answer:

y = \frac{\pi}{2}cos(\frac{2\pi}{3}x)

Step-by-step explanation:

Given

Amplitude = \frac{\pi}{2}

Period = 3

Required

Write the equivalent cosine function

The general formula is:

y = acos(bx)

Where

amplitude = |a|

period = \frac{2\pi}{b}

Substitute \frac{\pi}{2} for amplitude in amplitude = |a|

|a| = \frac{\pi}{2}

a = \frac{\pi}{2}

Substitute 3 for period in period = \frac{2\pi}{b}

\frac{2\pi}{b} = 3

<em>Multiply both sides by b</em>

2\pi = 3b

<em>Divide through by 3</em>

b = \frac{2\pi}{3}

Hence;

y = acos(bx) becomes

y = \frac{\pi}{2}cos(\frac{2\pi}{3}x)

5 0
3 years ago
Who’s the president?
MAVERICK [17]

Answer: Donald J. Trump

Step-by-step explanation: 45th president of the United States

4 0
3 years ago
For f (x) - 4x +1 and g(x) = ? -5, find (fºg)(4).
Alona [7]

(f\circ g)(x)=f(g(x))=4(x^2-5)+1=4x^2-19

(f\circ g)(4)=4\cdot4^2-19=64-19=\boxed{45}

Hope this helps.

5 0
2 years ago
|2n+5|&gt;/9 solve for n?
levacccp [35]
|2n+5|\geq9\iff2n+5\geq9\ or\ 2n+5\leq-9\ \ \ |subtract\ 5\ from\ both\ sides\\\\2n\geq4\ or\ 2n\leq-14\ \ \ \ \ |divide\ both\ sides\ by\ 2\\\\\boxed{n\geq2\ or\ n\leq-7}\\\\Answer:\boxed{\boxed{n\in(-\infty;-7]\ \cup\ [2;\ \infty)}}
5 0
3 years ago
Read 2 more answers
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