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andriy [413]
3 years ago
10

On Monday Sarah had homework in 7⁄10 of her classes, Tuesday 3⁄5 , Wednesday 9⁄11 , and Thursday 1⁄2 . Which day did she have th

e mosthomework
Mathematics
1 answer:
expeople1 [14]3 years ago
5 0
9/11, just choose the biggest fraction
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Find two geometric means between 5 and 135
aniked [119]
Answer:

We are effectively looking for a and b such that 5, a, b, 135 is a geometric sequence.

This sequence has common ratio <span><span>3<span>√<span>1355</span></span></span>=3</span>, hence <span>a=15</span> and <span>b=45</span>

Explanation:

In a geometric sequence, each intermediate term is the geometric mean of the term before it and the term after it.

So we want to find a and b such that 5, a, b, 135 is a geometric sequence.

If the common ratio is r then:

<span><span>a=5r</span><span>b=ar=5<span>r2</span></span><span>135=br=5<span>r3</span></span></span>

Hence <span><span>r3</span>=<span>1355</span>=27</span>, so <span>r=<span>3<span>√27</span></span>=3</span>

Then <span>a=5r=15</span> and <span>b=ar=15⋅3=45</span>


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