Yes it is (10x-y)^2 is the answer of it
Note: Let us consider, we need to find the
and
.
Given:
In the given figure, BD is the angle bisector of ABC.
To find:
The
and
.
Solution:
BD is the angle bisector of ABC. So,
![m\angle ABD=m\angle DBC](https://tex.z-dn.net/?f=m%5Cangle%20ABD%3Dm%5Cangle%20DBC)
![3x=x+20](https://tex.z-dn.net/?f=3x%3Dx%2B20)
![3x-x=20](https://tex.z-dn.net/?f=3x-x%3D20)
![2x=20](https://tex.z-dn.net/?f=2x%3D20)
Divide both sides by 2.
![x=\dfrac{20}{2}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B20%7D%7B2%7D)
![x=10](https://tex.z-dn.net/?f=x%3D10)
Now,
![m\angle DBC=(x+20)^\circ](https://tex.z-dn.net/?f=m%5Cangle%20DBC%3D%28x%2B20%29%5E%5Ccirc)
![m\angle DBC=(10+20)^\circ](https://tex.z-dn.net/?f=m%5Cangle%20DBC%3D%2810%2B20%29%5E%5Ccirc)
![m\angle DBC=30^\circ](https://tex.z-dn.net/?f=m%5Cangle%20DBC%3D30%5E%5Ccirc)
And,
![m\angle ABC=(3x)^\circ+(x+20)^\circ](https://tex.z-dn.net/?f=m%5Cangle%20ABC%3D%283x%29%5E%5Ccirc%2B%28x%2B20%29%5E%5Ccirc)
![m\angle ABC=(4x+20)^\circ](https://tex.z-dn.net/?f=m%5Cangle%20ABC%3D%284x%2B20%29%5E%5Ccirc)
![m\angle ABC=(4(10)+20)^\circ](https://tex.z-dn.net/?f=m%5Cangle%20ABC%3D%284%2810%29%2B20%29%5E%5Ccirc)
![m\angle ABC=(40+20)^\circ](https://tex.z-dn.net/?f=m%5Cangle%20ABC%3D%2840%2B20%29%5E%5Ccirc)
![m\angle ABC=60^\circ](https://tex.z-dn.net/?f=m%5Cangle%20ABC%3D60%5E%5Ccirc)
Therefore,
and
.
48:24 = 24:12 = 12:6 = 6:3 (divide each number by 2 or multiply by 2)
Answer:
15x+25
Step-by-step explanation:
cancel out (2x+1) you'll be left with 5(3x+5)
when multiply 5 by 3x+5
Answer:
80 m^2
Step-by-step explanation:
The formula is lwh/3. 5*6*8=240 240/3=80