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viva [34]
4 years ago
10

What is the value of m?

Mathematics
1 answer:
horsena [70]4 years ago
3 0
I'm assuming they are equivalent...

5m + 1 = 3m + 7

Solve for m and get 3.

~~

I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey
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The sum of two polynomials is 8d5 – 3c3d2 + 5c2d3 – 4cd4 + 9. If one addend is 2d5 – c3d2 + 8cd4 + 1, what is the other addend?
lidiya [134]
This one is a bit confusing but I'll try to answer. Since the sum is given and one of the addend is given, we need to perform subtraction to get the other addend.

     8d⁵ - 3c³d² + 5c²d³ - 4cd⁴ + 9  ⇒ SUM
<u>-    2d⁵ -   c³d²              + 8cd⁴ + 1 </u> ⇒ 1ST ADDEND
     6d⁵ - 2c³d² + 5c²d³ -12cd⁴ - 8 ⇒ 2ND ADDEND


8 0
3 years ago
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Will give brainliest if the answer is correct!!! Help ASAP!!!!
Zepler [3.9K]

Answer:

Parallel lines

Step-by-step explanation:

3 0
3 years ago
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Do not round your answer. Type in just the number.<br> 35 is 25% of
oksano4ka [1.4K]

Answer:

8.75

Step-by-step explanation:

35 * 0.25 = 8.75

Hope it helps you in your learning process

6 0
3 years ago
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2 + 2 - 1<br><br>I really need help​
shutvik [7]

Answer:

3

Step-by-step explanation:

Break the problem up into two

Ignore the -1 for now

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Now that you have four, subtract 1

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5 0
3 years ago
Two number cubes are rolled sequentially. What is the probability that the first number cube shows a five and the other number c
nexus9112 [7]

The probability of first number cube shows a five and the other number cube shows an even number is \frac{1}{12}.

Solution:

Two cubes are rolled sequentially.

Sample space when two dies are rolled

                   =\left\{\begin{array}{l}{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)} \\{(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)} \\{(3,1), 3(, 2),(3,3),(3,4),(3,5),(3,6)} \\{(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)} \\{(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)} \\{(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}\end{array}\right\}

Number of sample space = 36

Even numbers getting when two cubes rolled are 2, 4, 6.

First number cube shows a five and the other number cube shows an even number = {(5, 2), (5, 4), (5 6)}

Number of first number cube shows a five and the other number cube shows an even number = 3

Probability of first number cube shows a five and the other number cube shows an even number

                 $=\frac{\text{Number of outcomes}}{\text{Total number of sample space}} $

                $=\frac{3}{36}

                $=\frac{1}{12}

Hence, the probability of first number cube shows a five and the other number cube shows an even number is \frac{1}{12}.

8 0
3 years ago
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