If the hitter makes an out 72% of the time, then the probabilty that he makes hit in 1 at-bat is $p=0.72$ and the probabilty that he doesn't make hit in 1 at-bat is $q=1-p=1-0.72=0.28.$

The probability that the hitter makes 10 outs in 10 consecutive at-bats, assuming at-bats are independent events is

$P=p^{10}=(0.72)^{10}\approx 0.037.$

5 0

3 years ago

Find the 100th term of the following arithmetic sequence <br> 5.5, 6, 6.5, 7, ...

AysviL [449]

Answer:

Step-by-step explanation:

The n-th term of an arithmetic sequence is given by the formula ...

an = a1 + d(n -1)

where a1 is the first term (5.5) and d is the common difference (0.5).

So, the n-th term is ...

an = 5.5 +0.5(n -1) = 5.0 +0.5n

For n = 100, the term is ...

a100 = 5.0 +0.5(100) = 55

The 100th term of the sequence is 55.

8 0

4 years ago

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