I need help please, can you help me?
1 answer:
Answer:
x= 16 degrees
Step-by-step explanation:
the angles can be a little hard to remember but just know that the angles that are outside of the transversal are exterior angles and if they are on the opposite sides of the line that passes through the parallel lines then they're alternate exterior angles and those angles that are inside are interior angles and if they are on the opposite sides of the line passing through the parallel then they are alternate interior angles .
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Answer: The proof is mentioned below.
Step-by-step explanation:
Here, Δ ABC is isosceles triangle.
Therefore, AB = BC
Prove: Δ ABO ≅ Δ ACO
In Δ ABO and Δ ACO,
∠ BAO ≅ ∠ CAO ( AO bisects ∠ BAC )
∠ AOB ≅ ∠ AOC ( AO is perpendicular to BC )
BO ≅ OC ( O is the mid point of BC)
Thus, By ASA postulate of congruence,
Δ ABO ≅ Δ ACO
Therefore, By CPCTC,
∠B ≅ ∠ C
Where ∠ B and ∠ C are the base angles of Δ ABC.
