Answer:
4.1n
Step-by-step explanation:
Let's simplify step-by-step.
n−4.6n−3.3n+2.8n
=n+−4.6n+−3.3n+2.8n
Combine Like Terms:
=n+−4.6n+−3.3n+2.8n
=(n+−4.6n+−3.3n+2.8n)
=−4.1n
is continuous over its domain, all real
.
Meanwhile,
is defined for real
.
If
, then we have
as the domain of
.
We know that if
and
are continuous functions, then so is the composite function
.
Both
and
are continuous on their domains (excluding the endpoints in the case of
), which means
is continuous over
.
Alright, take it step by step...in month one, they had 5 members.
if the number doubles each month, then the second month they will have a total of ten members, right? in the third they will have twice the number before, or 2 times 10, 20. if you double 20, you have the number of people in the fourth month, giving you a grand total of 40.
Answer:
(x+1)²/6 - (y+3)²/12 = 1
Step-by-step explanation:
The standard form of writing the equation of an hyperbola is expressed as;
(x-h)²/a² - (y-b)²/b² = 1 where (h,k) is the centre of the hyperbola.
Given the equation:
6x²-3y²+12x-18y-3 = 0
We are to convert it to the standard form of writing the equation of a hyperbola.
Collecting the like terms will give;
(6x²+12x)-(3y²+18y)-3 = 0
Divide through by 3
(2x²+4x)-(y²+6y)-1 = 0
Completing the square of the equation in parenthesis and adding the constants to the other side of the equation:
(2x²+4x)-(y²+6y+(6/2)²)-1 = 0+(6/2)²
(2x²+4x)-(y²+6y+9)-1 = 9
2x²+4x -{(y+3)²} = 9+1
2x²+4x - (y+3)² = 10
Divide through by 2
x²+2x -(y+3)²/2 = 5
(x²+2x+(2/2)²)-(y+3)²/2 = 5+(2/2)²
(x²+2x+1) - (y+3)²/2 = 5+1
(x+1)²-(y+3)²/2 = 6
Divide through by 6
(x+1)²/6 - (y+3)²/12 = 1
The resulting equation is the required standard form of a hyperbola with centre at (-1, -3)
Answer:
11.4
Step-by-step explanation:
Distance=sqrt(7^2+9^2)=sqrt(130)=11.4
