Answer:
A) the y-intercept of g(x) is less than the y-intercept of f(x).
Answer:
<h2>2</h2>
Step-by-step explanation:
Given g(x)=5x-4 and g(x)=f^{-1}(x)-3
Substituting g(x) = 5x-4 into the second equation we have;
5x-4 = f^{-1}(x)-3
f^{-1}(x) = 5x-4+3
f^{-1}(x) = 5x-1
To get f(x), let us first make y to be equal f^{-1}(x)
y = 5x-1
expressing x in terms of y to get f(x), we have;
5x = y+1
x = y/5+1/5
replacing y with x, we will have;
y = x/5 + 1/5
F(x) = x/5 + 1/5
Comparing x/5 + 1/5 with ax+b, a = 1/5 and b = 1/5
5a + 5b = 5(1/5)+ 5(1/5)
5a+5b = 1+1
5a+5b = 2
The function notation f(x)=2x-4 means replace the x on the right-hand side with the value in parentheses on the left.
For example, f(y)=2y-4; f(4)=2(4)-4=4; f(1)=2(1)-4=-2 and so on.
The same principle applies to g(x), for example
g(2)=4(2^2)-3=13,
g(x+1)=4(x+1)^2-3=4(x^2+2x+1)-3=4x^2+8x+4-3=4x^2+8x+1
and so on.
(g of f)(x) is another way to write g(f(x)), therefore
g(f(x))
=g(2x-4) [because f(x)=2x-4
=4(2x-4)^2-3
=4(4x^2-16x+16)-3
=16x^2-64x+64-3
=16x^2-64x+61
Find three consecutive odd integral such that the sum of seven times the smallest and twice the largest is -91
Steps to solve:
15 + 2a = 35
~Subtract 15 to both sides
2a = 20
~Divide 2 to both sides
a = 10
Best of Luck!
