You save 5 cents per ounce by using the 40 ounce jar, because if you do $5.20 divided by 40 it equals $0.13 but if you do $2.70 divided by 15 it equals $0.18 which is 5 more cents the the 40 ounce
Answer:
1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle
Step-by-step explanation:
Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is
V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³
the mass in that volume would be m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)
The density of an alpha particle is ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be
ρ= m/V
since both should be equal ρ=ρa , then
ρa= m/V =N*L/V → N =ρa*V/L
replacing values
N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg = 1.544*10⁹ Linebackers
N=1.544*10⁹ Linebackers
Answer:
Option B is correct.
The value of x is, 0
Step-by-step explanation:
Given the system of equation:
-x+2y =6 .....[1]
6y =x+18 ......[2]
We can write equation [1] as;
-x = 6-2y or
x = -6 + 2y ......[3]
Substitute equation [3] in [2] we get;
6y =-6 + 2y + 18
or
6y = 2y +12
Subtract 2y from both sides we get;
6y -2y = 2y+ 12 -2y
Simplify:
4y = 12
Divide both sides by 4 we get;
Simplify:
y =3
Substitute the value of y in equation [3] to solve for x;
x = -6 + 2(3)
x = -6 +6 = 0
Therefore, the value of x is, 0
He drove 219.375 miles more on the fist day than the second day.
