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enyata [817]
3 years ago
9

Answer asap!!!!!!!!!!!!!!!!

Mathematics
1 answer:
MAXImum [283]3 years ago
4 0

Answer:

-2

Step-by-step explanation:

From the graph, it appears that (0, 2) and (2, -2) are points on the line.  (Othere points will work, as well; you just need two points.)

Slope = (difference between the y coordinates) / (difference between the x coordinates)

One phrase to remember this is slope = "rise over run"  (vertical change divided by horizontal change from point to point).

Slope = (-2 - 2) / (2 - 0) = -4 / 2 = -2

The slope is -2.

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Factor completely.<br> 28 - 7x^2
Studentka2010 [4]

Answer:

−7x^2+28

Step-by-step explanation:

28−7x^2

=28+−7x^2

=−7x^2+28

6 0
4 years ago
3. Jessica is awake 2/3 of the day. She spends 5/8 of this time at home
ruslelena [56]

Answer:  a. 5/12     b. 10 hours

Step-by-step explanation:

5/8 x 2/3 = 10/24 = 5/12

she spends 5/12 of the day awake at home

if a day has 24 hours then 5/12 of that is 5/12 x 24 = 10

so she spends 10 hours awake at home

7 0
4 years ago
A certain fluid is not a liquid if its temperature above 140 C or below 0 C. Enter a compound inequality for the temperatura t w
tiny-mole [99]

Answer:

t < 0 and t > 140

Step-by-step explanation:

It is given in the question that fluid is not a liquid if its temperature is above 140°C or below 0°C.

So, the inequality that satisfies the temperature at which the fluid is liquid will be given by 140 ≥ t ≥ 0.

Now, the compound inequality for the temperature t when the fluid is not liquid is t < 0 and t > 140. (Answer)

5 0
4 years ago
If sin theta = (4)/(7)​, theta in quadrant​ II, find the exact value of (a) cos theta (b) sin (theta + (pi) / (6) ) (c) cos (the
EleoNora [17]

Answer:

a) \cos(\theta) = \frac{\sqrt[]{33}}{7}

b) \sin(\theta + \frac{\pi}{6})\frac{-3\sqrt[]{11}+4}{14}

c) \cos(\theta-\pi)=\frac{\sqrt[]{33}}{7}

d)\tan(\theta + \frac{\pi}{4}) = \frac{\frac{-4}{\sqrt[]{33}}+1}{1+\frac{4}{\sqrt[]{33}}}

Step-by-step explanation:

We will use the following trigonometric identities

\sin(\alpha+\beta) = \sin(\alpha)\cos(\beta)+\cos(\alpha)\sin(\beta)

\cos(\alpha+\beta) = \cos(\alpha)\cos(\beta)-\sin(\alpha)\sin(\beta)\tan(\alpha+\beta) = \frac{\tan(\alpha)+\tan(\beta)}{1-\tan(\alpha)\tan(\beta)}.

Recall that given a right triangle, the sin(theta) is defined by opposite side/hypotenuse. Since we know that the angle is in quadrant 2, we know that x should be a negative number. We will use pythagoras theorem to find out the value of x. We have that

x^2+4^2 = 7 ^2

which implies that x=-\sqrt[]{49-16} = -\sqrt[]{33}. Recall that cos(theta) is defined by adjacent side/hypotenuse. So, we know that the hypotenuse is 7, then

\cos(\theta) = \frac{-\sqrt[]{33}}{7}

b)Recall that \sin(\frac{\pi}{6}) =\frac{1}{2} , \cos(\frac{\pi}{6}) = \frac{\sqrt[]{3}}{2}, then using the identity from above, we have that

\sin(\theta + \frac{\pi}{6}) = \sin(\theta)\cos(\frac{\pi}{6})+\cos(\alpha)\sin(\frac{\pi}{6}) = \frac{4}{7}\frac{1}{2}-\frac{\sqrt[]{33}}{7}\frac{\sqrt[]{3}}{2} = \frac{-3\sqrt[]{11}+4}{14}

c) Recall that \sin(\pi)=0, \cos(\pi)=-1. Then,

\cos(\theta-\pi)=\cos(\theta)\cos(\pi)+\sin(\theta)\sin(\pi) = \frac{-\sqrt[]{33}}{7}\cdot(-1) + 0 = \frac{\sqrt[]{33}}{7}

d) Recall that \tan(\frac{\pi}{4}) = 1 and \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}=\frac{-4}{\sqrt[]{33}}. Then

\tan(\theta+\frac{\pi}{4}) = \frac{\tan(\theta)+\tan(\frac{\pi}{4})}{1-\tan(\theta)\tan(\frac{\pi}{4})} = \frac{\frac{-4}{\sqrt[]{33}}+1}{1+\frac{4}{\sqrt[]{33}}}

5 0
3 years ago
6.50 is 25$ of what number?
Ivenika [448]

Answer:

3.85

Step-by-step explanation:

6.50 goes into 25 how many times

6.50×?=25

6.50 divided by 25 = 3.846153846

Simplify

3.85

8 0
3 years ago
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