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3 years ago

Please help algebra 2!!

Mathematics

1 answer:

RUDIKE [14]3 years ago

7 0

Let u = x^2

u^2 + 12u - 64

(u - 4)(u + 16)

Back-substitute for u.

(x^2 - 4)(x^2 + 16)

(x + 2)(x - 2)(x + 4i)(x - 4i)

Answer: Choice a.

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hellen raised 12$ for the food bank last year and she raised 6 times as much money this year how much money did she raise this y

loris [4]

Answer:

72$

Step-by-step explanation:

6x12=72

7 0

3 years ago

What is the equivalent amount in year ten of an expenditure of $5,000 in year one, $6,000 in year two, and amounts increasing by

Archy [21]

Answer:

The correct answer is the equivalent amount is $139,059.41

Step-by-step explanation:

According to the scenario, the computation of the equivalent amount in year ten is shown below;

= $5,000 × (P/A, 10%,10) + $1,000 × (P/G, 10%,10)

= $5,000 × 6.1466 + $1,000 × 22.8913

= $30,723 + $22,891.30

= $53,614.30

Now the equivalent amount is

= $53,614.30 × (F/P, 10%,10)

= $53,614.30 × 2.5937

= $139,059.41

Hence, the equivalent amount is $139,059.41

3 0

2 years ago

What's 723 divided by 31 please show work!!

mojhsa [17]

732/31= 23.612 (3dp)
it’s hard to show your working out when you don’t know the 31 times table

8 0

3 years ago

Base: z(x)=cosx Period:180 Maximum:5 Minimum: -4 What are the transformation? Domain and Range? Graph?

garik1379 [7]

Answer:

The transformations needed to obtain the new function are horizontal scaling, vertical scaling and vertical translation. The resultant function is $z'(x) = \frac{1}{2} + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right)$ .

The domain of the function is all real numbers and its range is between -4 and 5.

The graph is enclosed below as attachment.

Step-by-step explanation:

Let be $z (x) = \cos x$ the base formula, where $x$ is measured in sexagesimal degrees. This expression must be transformed by using the following data:

$T = 180^{\circ}$ (Period)

$z_{min} = -4$ (Minimum)

$z_{max} = 5$ (Maximum)

The cosine function is a periodic bounded function that lies between -1 and 1, that is, twice the unit amplitude, and periodicity of $2\pi$ radians. In addition, the following considerations must be taken into account for transformations:

1) $x$ must be replaced by $\frac{2\pi\cdot x}{180^{\circ}}$ . (Horizontal scaling)

2) The cosine function must be multiplied by a new amplitude (Vertical scaling), which is:

$\Delta z = \frac{z_{max}-z_{min}}{2}$

$\Delta z = \frac{5+4}{2}$

$\Delta z = \frac{9}{2}$

3) Midpoint value must be changed from zero to the midpoint between new minimum and maximum. (Vertical translation)

$z_{m} = \frac{z_{min}+z_{max}}{2}$

$z_{m} = \frac{1}{2}$

The new function is:

$z'(x) = z_{m} + \Delta z\cdot \cos \left(\frac{2\pi\cdot x}{T} \right)$

Given that $z_{m} = \frac{1}{2}$ , $\Delta z = \frac{9}{2}$ and $T = 180^{\circ}$ , the outcome is:

$z'(x) = \frac{1}{2} + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right)$

The domain of the function is all real numbers and its range is between -4 and 5. The graph is enclosed below as attachment.

8 0

3 years ago

NEED ANSWER NOW PLEASE

Sonja [21]

Answer is 51.2 simplified

5 0

3 years ago