The perimeter is the sum of all sides. Start by listing out what the sides are given to be. Assign a variable to anything unknown.
1st side = x
2nd side = y
3rd side = z
Given: 1st side is 5 less than 2nd side.
x = y - 5
Given: 3rd side is 2 less that 1st side. But we want everything in only one variable to solve. So use the first given 1st side = y - 5
z = y - 5 - 2
z = y - 7
Sum of sides
(y - 5) + y + ( y - 7) = 42
3y - 12 = 42
3y = 42 + 12
3y = 54
y = 54/3
y = 18
Remember the sides, We have
1st, x = y - 5
= 18 - 5
= 13
2nd, y = y
= 18
3rd, z = y - 7
= 18 - 7
= 11
The answer is c.
a ruler should be used to measure an earthworm
If 1/3 is converted to a decimal it would be called a repeating decimal. Which means that the decimal will never end so the answer would be written as
0.33...
hope this answers your question
Answer:
= $477
Step-by-step explanation:
Amount that needs to be raised by each student = $53
Total number of students = 9
Next, use the above two numbers to calculate the total amount the club needs to raise;
Total amount of money that needs to be raised = Amount that needs to be raised by each student * Total number of students
Total amount = $53 * 9
= $477
Answer:
![x \approx 729](https://tex.z-dn.net/?f=x%20%5Capprox%20729)
Step-by-step explanation:
Given
Let the number be x
So:
![x + 10\sqrt x = 1000](https://tex.z-dn.net/?f=x%20%2B%2010%5Csqrt%20x%20%3D%201000)
Required
Using trial and improvement, find x
This implies that we keep guessing the values of x until we get a value that match the equation.
Let
![x = 625](https://tex.z-dn.net/?f=x%20%3D%20625)
So, we have:
![x + 10\sqrt x = 1000](https://tex.z-dn.net/?f=x%20%2B%2010%5Csqrt%20x%20%3D%201000)
![625 + 10 *\sqrt{625}](https://tex.z-dn.net/?f=625%20%2B%2010%20%2A%5Csqrt%7B625%7D)
Take the square root of 625
![625 + 10 *\sqrt{625} = 625 + 10 *25](https://tex.z-dn.net/?f=625%20%2B%2010%20%2A%5Csqrt%7B625%7D%20%3D%20625%20%2B%2010%20%2A25)
![625 + 10 *\sqrt{625} = 625 + 250](https://tex.z-dn.net/?f=625%20%2B%2010%20%2A%5Csqrt%7B625%7D%20%3D%20625%20%2B%20250)
![625 + 10 *\sqrt{625} = 875](https://tex.z-dn.net/?f=625%20%2B%2010%20%2A%5Csqrt%7B625%7D%20%3D%20875)
Let
![x = 729](https://tex.z-dn.net/?f=x%20%3D%20729)
So, we have:
![x + 10\sqrt x = 1000](https://tex.z-dn.net/?f=x%20%2B%2010%5Csqrt%20x%20%3D%201000)
![729 + 10 * \sqrt{729}](https://tex.z-dn.net/?f=729%20%2B%2010%20%2A%20%5Csqrt%7B729%7D)
Take the square root of 729
![729 + 10 * \sqrt{729} = 729 + 10 * 27](https://tex.z-dn.net/?f=729%20%2B%2010%20%2A%20%5Csqrt%7B729%7D%20%3D%20729%20%2B%2010%20%2A%2027)
![729 + 10 * \sqrt{729} = 729 + 270](https://tex.z-dn.net/?f=729%20%2B%2010%20%2A%20%5Csqrt%7B729%7D%20%3D%20729%20%2B%20270)
![729 + 10 * \sqrt{729} = 999](https://tex.z-dn.net/?f=729%20%2B%2010%20%2A%20%5Csqrt%7B729%7D%20%3D%20999)
At this point, we can conclude that x is approximately 729 because
![999 \approx 1000](https://tex.z-dn.net/?f=999%20%5Capprox%201000)
So:
![x \approx 729](https://tex.z-dn.net/?f=x%20%5Capprox%20729)