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andrew11 [14]
3 years ago
14

Identify the equation in slope intercept from that has a slope of 2 and goes through the point (4, 6).

Mathematics
2 answers:
tresset_1 [31]3 years ago
8 0

Answer:

D) y=2x-2

Step-by-step explanation:

y-y1=m(x-x1)

y-6=2(x-4)

y=2x-8+6

y=2x-2

Mars2501 [29]3 years ago
5 0

Answer:

  y = 2x−2

Step-by-step explanation:

You are given a slope and a point, so you can write the equation using point-slope form:

  y -k = m(x -h) . . . . . . a line with slope m through point (h, k)

Putting in the numbers given, you have ...

  y -6 = 2(x -4)

  y = 2x -8 +6 . . . . eliminate parentheses, add 6

  y = 2x -2 . . . . . . . collect terms.

__

You know that the slope is the coefficient of x, so the first choice is eliminated right away. Trying the point values in the other equations shows you that they only work for the last choice, as shown above.

  • 2·4 +14 = 22 ≠ 6 . . . . second choice doesn't work
  • 2·4 +6 = 14 ≠ 6 . . . . . third choice doesn't work
  • 2·4 -2 = 6 . . . . . . y = 2x-2 is the equation that works
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irinina [24]

For the given data set

Minimum = 48

Lower quartile = 55

Median = 63.5

Upper quartile = 74

Maximum = 80

Interquartile range = 19

<h3>Measures of a Data </h3>

From the question, we are to determine the minimum, lower quartile, median, upper quartile, maximum, and interquartile range of the given data set

The given data set is

48, 50, 54, 56, 63, 63, 64, 68, 74, 74, 79, 80

Minimum = 48

Lower quartile = (54+56)/2

Lower quartile = 110/2

Lower quartile = 55

Median = (63+64)/2

Median = 127/2

Median = 63.5

Upper quartile = (74+74)/2

Upper quartile = 148/2

Upper quartile = 74

Maximum = 80

Interquartile range = Upper quartile - Lower quartile

Interquartile range = 74 - 55

Interquartile range = 19

Hence, for the given data set

Minimum = 48

Lower quartile = 55

Median = 63.5

Upper quartile = 74

Maximum = 80

Interquartile range = 19

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a. Find the graph of their common region in the attachment

b. The area of the common region of the graphs is 8 units²

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Since we have x ≥ 2, y ≥ 0, and x + y ≤ 6, we plot each graph separately and find their region of intersection.

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  • The graph of y ≥ 0 is the region above the line y = 0 or x-axis.
  • To plot the graph of x + y ≤ 6, we first plot the graph of x + y = 6 ⇒ y = -x + 6. Then the graph of x + y ≤ 6 is the graph of y ≤ - x + 6.

So, the graph of x + y ≤ 6 is the region below the line y = - x + 6

From the graph, the regions intersect at (2, 0), (2, 4) and (6, 0)

Find the graph of their common region in the attachment

<h3>b. The area of the common region</h3>

From the graph, we see that the common region is a right angled triangle with

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So, its area = 1/2 × height × base

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So, the area of the common region of the graphs is 8 units²

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Step-by-step explanation:

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