First of all,
The total weight of the six dogs are:
71+34+15+23+18+56=217 pounds
Then, we know that the average weight of the seven dogs are 40 pounds, so the total weights of the seven dogs are:
40×7=280 pounds.
Lastly, we know that the six dogs weights are 217 pounds and the total weight of the seven dogs are 280 dogs, so the seventh weight of the dog is:
280-217=63 pounds. As a result, the seventh weight of the dogs at the vet is 63 pounds. Hope it help!
Dont say you can't! I believe in youu!
<u><em>Answers:</em></u>
(2,1)
(1,3)
<u><em>Explanation:</em></u>
Assume that the number of hot dogs is x and the number of water bottles is y.
<u>We are given that:</u>
1- cost of hot dog is $4
2- cost of water is $2
3- total profit was less than $12
<u>This means that:</u>
4x + 2y < 12
<u>We will check the options that satisfy the above inequality:</u>
<u>Option 1: (-1,5):</u>
This option is rejected as we cannot sell -1 hot dog
<u>Option 2: (0,6):</u>
4x + 2y = 4(0) + 2(6) = 12
12 is not less than 12
This option is incorrect
<u>Option 3: (2,1):</u>
4x + 2y = 4(2) + 2(1) = 8 + 2 = 10
10 is less than 12
This option is correct
<u>Option 4: (1,1.5):</u>
This option is incorrect as we cannot sell 1.5 bottle of water
<u>Option 5: (1,3):</u>
4x + 2y = 4(1) + 2(3) = 4 + 6 = 10
10 is less than 12
This option is correct
<u>Option 6: (2,2):</u>
4x + 2y = 4(2) + 2(2) = 8 + 4 = 12
12 is not less than 12
This option is incorrect
Hope this helps :)
2/3 is the answer. Try not to overthink these answers because they’re usually quite simple in the end. :)
