Awnser is c I just did this
Since triangle DEF = triangle JKL, m<D = m<J, m<E = m<K, m<F = m<L.
m<F = m<L = 90 degrees
m<K = m<E = 5(m<D)
but m<E + m<D = 90 degrees [right angled triangle]
5(m<D) + m<D = 90 degrees
6(m<D) = 90 degrees
m<D = 90 / 6 = 15 degrees.
Answer:
9/5 (K-273.15) + 32=F
Step-by-step explanation:
K=5 /9(F−32)+273.15
Subtract 273.15 from each side
K-273.15=5/9(F−32)+273.15-273.15
K-273.15=5/9(F−32)
Multiply by 9/5 on each side
9/5 (K-273.15)= 9/5 *5/9(F−32)
9/5 (K-273.15)=(F−32)
Add 32 to each side
9/5 (K-273.15) + 32=F−32 +32
9/5 (K-273.15) + 32=F
