52 cards in a deck. 4 of those are queens. 52/2=26 (total # of black cards), 2 red queens. Total + of cards you could possibly draw as the favored car = 28 out of 52...,
This is where i lose the probability. It's greater than 50%. I hope this helps.
All of the numbers are the mode, so it is
1982, 1988, 1989, 1994, 1995, 2005
F(x) = 20000 (1-0.15) power x
So
f(x) = 20000 (0.85) power x
Answer:
The probability that two of them
die is 0.257
Step-by-step explanation:
From the question, we have that the mortality rate is 0.1
So the probability that they will survive is 1-0.1 = 0.9
Now, we want to check that two will die
We are going you use the Bernoulli approximation of the Binomial theorem as follows
= nCr * p^n * q^(n-r)
where n = 16
r = 2
P = 0.1
q = 0.9
Substituting these values;
14 C 2 * 0.1^2 * 0.9^12
= 0.257
