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Mariulka [41]
3 years ago
14

If m<KHM-51.6° in the right triangle shown below , what is the measure of <KMH

Mathematics
1 answer:
vekshin13 years ago
3 0
180 - 90 - 51.6 = 38.4
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When you went to sleep, the temperature was −2.8°C.
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The larger the number the warmer it is

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4 years ago
What value of Y will satisfy the given equation y divided by 2y — 15 = 7/5​
guapka [62]

Answer:

\huge\boxed{\sf y = \frac{41}{5}  \ OR \ y = 8\frac{1}{5} }

Step-by-step explanation:

\sf 2y-15 = \frac{7}{5} \\\\Adding \ 15 \ to \ both \ sides\\\\2y = \frac{7}{5} + 15\\\\2y = \frac{7+75}{5} \\\\2y = \frac{82}{5} \\\\Dividing \ both \ sides \ bu 2\\\\y = \frac{82}{5*2} \\\\y = \frac{41}{5}

Hope this helped!

<h2>~AnonymousHelper1807</h2>
3 0
3 years ago
Brett and Max are diving. Brett is 34 feet below the surface and Max is 25 feet below the surface. How many feet above Brett isM
saveliy_v [14]

Answer:

Max is 9 ft above Brett

Step-by-step explanation:

Brett is 34 feet below the surface  = -34

Max is 25 feet below the surface = -25

Subtract the heights

-25 - -34

-25 +34

9

Max is 9 ft above Brett

6 0
3 years ago
Read 2 more answers
Anika is hiking on a rectangular trail at the national park. There are four resting spots along the corners of the trail. On the
tia_tia [17]
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4 0
3 years ago
The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a
STatiana [176]

Answer:

24761 mosquitoes

5.4 days

Step-by-step explanation:

Let the equation that shows the population of the mosquitoes after x days,

A=P(1+r)^x

Where,

P = Initial population,

r = rate of increasing per day,

Here, A = 1000, when x = 0,

1000=P(1+r)^0\implies P = 1000

A = 1900 when x = 1,

1900 = P(1+r)^1\implies 1900 = 1000(1+r)\implies 1.9 = 1 + r\implies r = 0.9

Thus, the required function that represents the population after x days,

A=1900(1+0.9)^x=1900(1.9)^x

If x = 4,

The number of mosquito after 4 days,

A=1900(1.9)^4 = 24760.99\approx 24761

If A = 60,000,

60000 = 1900(1.9)^x

\frac{600}{19}=1.9^x

Taking log both sides,

\log(\frac{600}{19})=x\log 1.9

\implies x = \frac{\log(\frac{600}{19})}{\log 1.9}=5.378\approx 5.4

Thus, there will 60,000 mosquitoes after 5 days.

6 0
3 years ago
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