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3 years ago

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59:41 To build the roof for a paper house, a rectangular paper is cut to form a trapezoid. Which diagram shows the correct cuts?

Save and Exit Mark this and return Nes Submn K

2 answers:

Free_Kalibri [48]3 years ago

7 0

Answer:

Step-by-step explanation:

wheres the diagram?

lora16 [44]3 years ago

4 0

Answer:B

Step-by-step explanation:

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Can I please get help with this I give thanks

gladu [14]

First one :
We divide it into two rectangles (the top one has dimensions 2in*4in)

The area of the top rectangle is 2*4=8 in^2

The second rectangle has dimensions 3*(5-3)=6 in^2
Hence the total area is 8+6=14 square inches

Second one :
We divide it into a rectangle (dimensions 11*17) and a triangle on the top.

The area of the rectangle is 11*17=187 m^2
The rectangle has dimensions 17 (base's length) and 23-11 (height) hence its area is 17*(23-11)/2=102 m^2

Hence the total area is 102+187=289 square meters

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3 years ago

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PLS ANSWER THIS IM IN A HURRY

den301095 [7]

Answer:

14.14 i hope this helps lol ;)

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3 years ago

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Fill in the boxes below with the numbers 1-5.

Alja [10]

Answer:

4 - 2 - 3 - 1 - 5

Step-by-step explanation:

The substitute method consists of the following steps:

Solve for either x or y in one of the equations.
Substitute the expression you got into the other equation
Simplify and solve for the variable that remains.
Back substitute and solve for the first variable.
Check your solution

3 0

3 years ago

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The formula for wind chill C (in degrees Fahrenheit) is given by C = 35.74 + 0.6215T - 35.75v^0.16 + 0.4275Tv^0.16 where v is th

Diano4ka-milaya [45]

Answer:

dC = 2.44

Relative error = 19%

Step-by-step explanation:

$C = 35.74 + 0.6215*T - 35.75*v^(0.16) + 0.4275*T*v^(0.16)$

Δv = 3 ; ΔT = 1 , v = 23, T = 8

Use differential Calculus

$dC = Cv.dv + Ct.dt$

$Cv = dC/dv = -5.72*v^(-0.84) + 0.0684*T*v^(-0.84)\\Ct = dC/dT = 0.6215 + 0.4275*v^(0.16)\\dC = modulus (Cv.dv) + modulus (CT.dT)\\dC = (-5.72*v^(-0.84) + 0.0684*T*v^(-0.84))* 3 + (0.6215 + 0.4275*v^(0.16))*1\\dC = 2.44$

Relative Error

dC / C @(T = 8, v=23) * 100 = 19 %

8 0

3 years ago

According to the article "Characterizing the Severity and Risk of Drought in the Poudre River, Colorado" (J. of Water Res. Plann

mihalych1998 [28]

Answer:

(a) P (Y = 3) = 0.0844, P (Y ≤ 3) = 0.8780

(b) The probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

Step-by-step explanation:

The random variable <em>Y</em> is defined as the number of consecutive time intervals in which the water supply remains below a critical value <em>y₀</em>.

The random variable <em>Y</em> follows a Geometric distribution with parameter <em>p</em> = 0.409<em>.</em>

The probability mass function of a Geometric distribution is:

$P(Y=y)=(1-p)^{y}p;\ y=0,12...$

(a)

Compute the probability that a drought lasts exactly 3 intervals as follows:

$P(Y=3)=(1-0.409)^{3}\times 0.409=0.0844279\approx0.0844$

Thus, the probability that a drought lasts exactly 3 intervals is 0.0844.

Compute the probability that a drought lasts at most 3 intervals as follows:

P (Y ≤ 3) = P (Y = 0) + P (Y = 1) + P (Y = 2) + P (Y = 3)

$=(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409+(1-0.409)^{2}\times 0.409\\+(1-0.409)^{3}\times 0.409\\=0.409+0.2417+0.1429+0.0844\\=0.8780$

Thus, the probability that a drought lasts at most 3 intervals is 0.8780.

(b)

Compute the mean of the random variable <em>Y</em> as follows:

$\mu=\frac{1-p}{p}=\frac{1-0.409}{0.409}=1.445$

Compute the standard deviation of the random variable <em>Y</em> as follows:

$\sigma=\sqrt{\frac{1-p}{p^{2}}}=\sqrt{\frac{1-0.409}{(0.409)^{2}}}=1.88$

The probability that the length of a drought exceeds its mean value by at least one standard deviation is:

P (Y ≥ μ + σ) = P (Y ≥ 1.445 + 1.88)

= P (Y ≥ 3.325)

= P (Y ≥ 3)

= 1 - P (Y < 3)

= 1 - P (X = 0) - P (X = 1) - P (X = 2)

$=1-[(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409\\+(1-0.409)^{2}\times 0.409]\\=1-[0.409+0.2417+0.1429]\\=0.2064$

Thus, the probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

6 0

3 years ago