Answer:
Step-by-step explanation:
y = sin(t^2)
y' = 2tcos(t^2)
y'' = 2cos(t^2) - 4t^2sin(t^2)
so the equation become
2cos(t^2) - 4t^2sin(t^2) + p(t)(2tcos(t^2)) + q(t)sin(t^2) = 0
when t=0, above eqution is 2. That is, there does not exist the solution. so y can not be a solution on I containing t=0.
See diagram
totalarea=totallengtht times totalwidth=(2a+5) times (2a+7)=4a²+24a+35
minus original aera
which is 5 by 7 which is 35
4a²+24a+35-35=4a²+24a
3rd option I think, can't tell which is which
The diagonal of a rectangle = sqrt(w^2 + l^2)
w = width
l = length
In this problem,
The diagonal = 20 in
w = x
l = 2x + 8
Let's plug our numbers into the formula above.
20in = sqrt((x)^2 + (2x + 8)^2)
Let's simplify the inside of the sqrt
20 in = sqrt(5x^2 + 32x + 64)
Now, let's square both sides.
400 = 5x^2 + 32x + 64
Subtract 400 from both sides.
0 = 5x^2 + 32x - 336
Factor
0 = (5x - 28)(x + 12)
Set both terms equal to zero and solve.
x + 12 = 0
Subtract 12 from both sides.
x = -12
5x - 28 = 0
Add 28 to both sides.
5x = 28
Divide both sides by 5
x = 28/5
The width cant be a negative number so now we know that the only real solution is 28/5
Let's plug 28/5 into our length equation.
Length = 2(28/5) + 8 = 56/5 + 8 = 96/5
In conclusion,
Length = 96/5 inches
Width = 28/5
Answer:
8f+4g
Step-by-step explanation:
distribute the 2 to 4f and 2g. Thats all you can do to the expression tho
Bob need to paint 205 square feet.
Solution:
Length of the door = 7 ft
Breadth of the door = 5 ft
Area of the door = length × breadth
= 7 × 5
= 35
Area of the door = 35 ft²
The given image is a trapezoid.
Top base = 12 ft
Bottom base = 20 ft
Area of the trapezoid = 


= 240
Area of the trapezoid = 240 ft²
Surface area to paint = Area of the trapezoid – Area of the door
= 240 ft² – 35 ft²
= 205 ft²
Hence Bob need to paint 205 square feet.