1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
katovenus [111]
3 years ago
6

5+ [14 + 5 - {6 (5 + 1 - 4)}] simplify​

Mathematics
1 answer:
IceJOKER [234]3 years ago
5 0

Answer:

12

Step-by-step explanation:

1) 5+19−6(5+1−4)

2)5+19−6(6−4)

3)5+19−(6)(2)

4)5+19−12

5) 5+7

6) 12

You might be interested in
Which expression is equivalent to 7h^2-252k^2?
gulaghasi [49]

Answer:

c

Step-by-step explanation:

252 = 7 *36

36 = 6 *6 = 6²

a² -b²  = (a + b)(a - b)

7h² - 252k² =  7(h² - 36k²)

                   = 7(h² - [6k]² )

                  = 7(h  +6k)(h - 6k)

6 0
3 years ago
Read 2 more answers
Eddie had 30 dollars to spend on 3 gifts. He spent 11
OverLord2011 [107]

Answer:

12.9 or 12 9/10

6 0
2 years ago
Only 4 please i need it by tomorrow
seraphim [82]
No she is not correct she needs to go back to school and learn math 
8 0
3 years ago
Can someone do this quick! I need the volume!!​
Dovator [93]

Answer:

1125000

Step-by-step explanation:

just multiply them all

4 0
3 years ago
Read 2 more answers
How many pairs of consecutive natural numbers have a product of less than 40000? I am in 5th grade. This is supposed to be easy
Ugo [173]

Answer:

There are 199 pairs of consecutive natural numbers whose product is less than 40000.

Step-by-step explanation:

We notice that such statement can be translated into this inequation:

n \cdot (n+1) < 40000

Now we solve this inequation to the highest value of n that satisfy the inequation:

n^{2}+n < 40000

n^{2}+n -40000

The Quadratic Formula shows that roots are:

n_{1,2} = \frac{-1\pm\sqrt{1^{2}-4\cdot (1)\cdot (-40000)}}{2\cdot (1)}

n_{1,2} = -\frac{1}{2}\pm \frac{1}{2} \cdot \sqrt{160001}

n_{1} = -\frac{1}{2}+\frac{1}{2}\cdot \sqrt{160001}

n_{1} \approx 199.501

n_{2} = -\frac{1}{2}-\frac{1}{2}\cdot \sqrt{160001}

n_{2} \approx -200.501

Only the first root is valid source to determine the highest possible value of n, which is n_{max} = 199. Each natural number represents an element itself and each pair represents an element as a function of the lowest consecutive natural number. Hence, there are 199 pairs of consecutive natural numbers whose product is less than 40000.

6 0
3 years ago
Other questions:
  • Which sentence is NOT a geometric progression?
    7·2 answers
  • 6(3m+5)=66<br> find m please
    10·2 answers
  • Do not under stand got confused and need help
    10·1 answer
  • What is the volume, to the nearest whole cubic inch, of a cylinder with a height of 10 inches and a radius of 8 inches
    11·1 answer
  • Find the value of -1/3-(-5/12)
    14·1 answer
  • Fill in the blank and dropdown menus to form a true statement below.​
    5·1 answer
  • Help me please !!! Only right answer please
    7·1 answer
  • Will mark brainliest!
    6·1 answer
  • What is the area of a circle with a radius of 6 inches?
    10·1 answer
  • Which expressions are equivalent to the on below select all that apply 9x
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!