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kompoz [17]
4 years ago
11

Is the fuel filter considered to be part of the cars engine?

Physics
1 answer:
nikdorinn [45]4 years ago
3 0
Yes it is concidered to be apart of the cars engine. 
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A proton is ejected from the sun at a speed of 2 x 10^6 m/s. How long does it take for this proton to reach earth? Answer in hou
wolverine [178]
The distance from the Sun to the Earth is 149,600,000 km.

d=149 600 000 \ km = 149 600 000 000 \ m = 1496 \cdot 10^8 \ m \\
v=2 \cdot 10^6 \ \frac{m}{s} \\ \\ \\
t=\frac{d}{v} \\ \\
t=\frac{1496 \cdot 10^8 \ m}{2 \cdot 10^6 \ \frac{m}{s}}=748 \cdot 10^2 \ s =\frac{748 \cdot 10^2 }{36 \cdot 10^2} \ h \approx \underline{\underline{20,78 \ h}}
5 0
3 years ago
after one hour, 1/16 of the initial amount of certain radioactive isotope remains undecayed. the half life of the isotope is:
Anarel [89]
(1/2)^x=1/16
ln 1/2^x=x ln 1/2=ln 1/16
x=4
4 half-lives in one hour=1/4 hour for the half-life of the isotope
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7 0
4 years ago
Read 2 more answers
Determine the wavelengths for Potassium (violet, λ = 400 nm) and Strontium (red, λ = 700 nm) light emissions. Calculate the freq
TEA [102]

Answer:

For Potassium:

Frequency = 7.5 x 10¹⁴ Hz; E (energy) = 8.83 x 10⁻²¹ J

For Strontium:

Frequency = 4.3 x 0¹⁴ Hz

E (energy) = 2.85 x 10⁻¹⁹ J

Explanation:

Wavelength is represented by λ, and Frequency is represented by ν .

E (energy) = hν = hc/λ,  where ν = frequency; c = speed of light = 3 x 10⁸ m/s; 1 s-1 = 1 Hz

h = planck's constant = 6.62 x 10⁻³⁴ J.s; 1 nm = 10⁻⁹ m

1. Potassium λ (wavelength) = 400 nm, Frequency, ν  is given by :

ν = c/λ = (3 x 10⁸  m/s) / 400 nm

  = (3 x 10⁸ m/s) / 400 x 10⁻⁹ s-1

  = 0.0075 x 10¹⁷s-1

  = 7.5 x 10¹⁴  s-1

Frequency = 7.5 x 10¹⁴ Hz

E (energy) = hν = (6.62 x 10⁻³⁴ J.s) x (7.5 x 10¹⁴s-1)

E (energy) = 8.83 x 10⁻²¹ J

2. Strontium λ (wavelength) = 700 nm ,Frequency, ν  is given by :

ν = c/λ = (3 x 10⁸ m/s) / 700 nm

  = (3 x 10⁸ m/s) / 700 x 10⁻⁹s-1

  = 0.00428571428 x 10¹⁷s-1

  = 4.3 x 10¹⁴ s-1

Frequency = 4.3 x 0¹⁴ Hz

E (energy) = hν = (6.62 x 10⁻³⁴ J.s) x (4.3 x 0¹⁴s-1)

E (energy) = 2.85 x 10⁻¹⁹ J

4 0
3 years ago
Read 2 more answers
When mapping the equipotentials on the plates with different electrode configurations you may find that some have significant ar
Olenka [21]

Answer:

v = 10 V and E = 2 10³ N/C

Explanation:

The electrical potentials and the electric field at one point are related by the expression

            ΔV = - ∫ E. dS

Where the bold indicates vector quantities, E is the electric field and S is the line of displacement of the load, in general displacement is perpendicular to the equipotential lines, which reduces the product scales to the ordinary product.

 If the potential difference is the most usual that is V = 10 V, the electric field is

   s = 0.5 cm = 0.5 10⁻² m

                E = ΔV / S

                E = 10/0.5 10⁻²

                 E = 2 10³ N / C

4 0
3 years ago
Explain the types of root​
Alex_Xolod [135]

Answer:

there are two main type of root systems.

6 0
3 years ago
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