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julia-pushkina [17]
4 years ago
10

A person wishes to heat pot of fresh water from 20°C to 100°C in order to boil water for pasta. They calculate that their pot ho

lds 2 kilograms of water. How much heat would have to be used to boil the water?
Physics
1 answer:
nasty-shy [4]4 years ago
6 0
Given:
Water, 2 kilograms
T1 = 20 degrees Celsius, T2 = 100 degrees Celsius.  

Required:
Heat produced  

Solution:
Q (heat) = nRT = nR(T2 = T1)
Q (heat) = 2 kilograms (4.184 kiloJoules per kilogram Celsius) (100 degrees Celsius – 20 degrees Celsius)
<u>Q (heat) = 669.42 Joules
</u>This is the amount of heat produced in boiling 2 kg of water.
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A thin Nichrome wire connected to an ammeter surrounds a region of time-varying magnetic flux, and the ammeter reads 13 amperes.
Semenov [28]

Answer:

The current would be same in both situation.

Explanation:

Given that,

Current I = 13 A

Number of turns = 23

We need to calculate the induced emf

Using formula of induced emf is

\epsilon=NA\dfrac{dB}{dt}

For N = 1

\epsilon=A\dfrac{dB}{dt}

We need to calculate the current

Using formula of current

i=\dfrac{\epsilon}{R}

Put the value of emf

i=\dfrac{A\dfrac{dB}{dt}}{R}

Now, if the number of turn is 22 , then induced emf would be

\epsilon'=NA\dfrac{dB}{dt}

Then the current would be

i'=\dfrac{\epsilon'}{NR}

i'=\dfrac{NA\dfrac{dB}{dt}}{NR}

i'=\dfrac{A\dfrac{dB}{dt}}{R}

i'=i

Hence, The current would be same in both situation.

4 0
3 years ago
What do you mean by Aquatic habitat? Give 2 examples of Desert habitat
Brilliant_brown [7]

Answer:

hope this answer will help you

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and what do u think about indians

8 0
3 years ago
What is the sound intensity level in a car when the sound intensity is 0.525 μW/m2 ? Use I0 = 1.00×10−12 W/m2 for the reference
never [62]

Answer:

The sound intensity level in the car is 57.2 dB.

Explanation:

Sound intensity level in decibels, β = 10 log (I/I₀); where I = 0.525 × 10⁻⁶ W/m², I₀ = 1.0 × 10⁻¹² W/m²

β (dB) = 10 log ((0.525 × 10⁻⁶)/(1.0 × 10⁻¹²)) = 10 × 5.72 = 57.2 dB

Hope this Helps!!!

8 0
3 years ago
At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball
dedylja [7]

Answer:

Magnitude of net force will be 432.758 N  

Explanation:

We have given x component of acceleration a_x=760m/sec^2

And vertical component of acceleration  a_y=770m/sec^2

Mass of the ball m = 0.40 kg

So net acceleration a=\sqrt{a_x^2+a_y^2}=\sqrt{760^2+770^2}=1081.896m/sec^2

Now according to second law of motion

Force = mass × acceleration

So F = 0.40×1081.896 = 432.758 N

3 0
3 years ago
It is very important that experiments are documented and<br> conducted with a procedure that can be?
Ksenya-84 [330]

Answer:

Repeated

Explanation:

An experiment must be done multiple times to prove its validity.

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5 0
3 years ago
Read 2 more answers
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